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emmynimmy
 one year ago
The equation y = 35.25x + 40 gives the labor cost y of repairing a car if it takes x hours to repair the car. Which statement is true?
For every hour of labor, the cost decreases by $40.
For every hour of labor, the cost decreases by $35.25.
For every hour of labor, the cost increases by $40.
For every hour of labor, the cost increases by $35.25.
emmynimmy
 one year ago
The equation y = 35.25x + 40 gives the labor cost y of repairing a car if it takes x hours to repair the car. Which statement is true? For every hour of labor, the cost decreases by $40. For every hour of labor, the cost decreases by $35.25. For every hour of labor, the cost increases by $40. For every hour of labor, the cost increases by $35.25.

This Question is Closed

Teddyiswatshecallsme
 one year ago
Best ResponseYou've already chosen the best response.0I believe its D.

emmynimmy
 one year ago
Best ResponseYou've already chosen the best response.1The equation y = 4.75x + 20 gives the cost y of towing a car if the car is towed x miles. According to the model, what is the best estimate of the cost for towing a car 22 miles? $24.75 $46.25 $104.50 $124.50

Teddyiswatshecallsme
 one year ago
Best ResponseYou've already chosen the best response.0Well its not negative so it wouldn't decline, and 40 doesn't represent the hourly cost so yeah. lol cx

emmynimmy
 one year ago
Best ResponseYou've already chosen the best response.1thanks! can you help with the other question?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0\[\large y = 4.75x + 20\] where 'x' is the number of miles...so since we want to know the cost to go 22 miles we have \[\large y = 4.75(22) + 20\] \[\large y = 104.5 + 20\] \[\large y = 124.5\]

Teddyiswatshecallsme
 one year ago
Best ResponseYou've already chosen the best response.0Yeah. Briefly. The answer for the second is 104.50

Teddyiswatshecallsme
 one year ago
Best ResponseYou've already chosen the best response.04.75(22) = 104.50

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0...close...but there is a constant added after that

emmynimmy
 one year ago
Best ResponseYou've already chosen the best response.1so that is not the answer?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0*refers to my post above :)

emmynimmy
 one year ago
Best ResponseYou've already chosen the best response.1The correlation coefficient (r) between the number of miles driven x and the number of gallons of gasoline used y is 0.925. What percent of the variation in the number of gallons of gasoline can be explained by differences in the number of miles driven? 7.5% 14.4% 85.6% 92.5%

Teddyiswatshecallsme
 one year ago
Best ResponseYou've already chosen the best response.0Oh i forgot about the 20.. Yeah, John's right. lolol. Most of these questions are easy you just plug in numbers for x or y and then just add or subtract or whatever.

emmynimmy
 one year ago
Best ResponseYou've already chosen the best response.1okay what about that ^^^

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Oh didn't see a reply So the correlation coefficient r = 0.925 What we need for variability is R^2 ...so .925^2 = 0.8556 And multiply that by 100 to get the percent which is 85.6%

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Oh crap, I hate this one haha I remember the long tedious steps to do this So I'm gonna cheat...1 sec :P

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0First choice sorry it took so long excel didnt wanna open for me lol :P

emmynimmy
 one year ago
Best ResponseYou've already chosen the best response.1no worries! thankyou!!

emmynimmy
 one year ago
Best ResponseYou've already chosen the best response.1Sorry, I'm literally trying so hard to turn all of my work in on time. Math is my worst subject.
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