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james1769

  • one year ago

Solve the equation the square root of the quantity x + 4 - 3 equals 1 for the variable. Show each step of your solution process.

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  1. Michele_Laino
    • one year ago
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    is your equation like this? \[\sqrt {x + 4} - 3 = 1\]

  2. james1769
    • one year ago
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    yes

  3. Michele_Laino
    • one year ago
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    since we have this square root \(\sqrt {x + 4} \), then we have to request that the radical \(x+4\) has to be greater or equal than zero: \[x + 4 \geqslant 0\]

  4. Michele_Laino
    • one year ago
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    since the square root of negative numbers doesn't exists

  5. james1769
    • one year ago
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    okay thanks

  6. Michele_Laino
    • one year ago
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    solving that inequality we have: \[x \geqslant - 4\] which means that we can accept, as solutions, only those quantities which are greater or equal to -4

  7. james1769
    • one year ago
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    does the answer come out to be x=12

  8. james1769
    • one year ago
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    got one more question

  9. Michele_Laino
    • one year ago
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    yes! since we have to add 3 to both sides: \[\sqrt {x + 4} = 4\] then squaring both sides and simplifying, we get: x=12

  10. Michele_Laino
    • one year ago
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    and since 12 > -4, we can conclude that x=12 is the solution of our equation

  11. james1769
    • one year ago
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    one more question

  12. Michele_Laino
    • one year ago
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    ok!

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