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anonymous

  • one year ago

Medal and Fan!!! *see attachment*

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    how would i do this?

  3. anonymous
    • one year ago
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    wut du u ned hulp wet?

  4. anonymous
    • one year ago
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    with the second part to the question

  5. anonymous
    • one year ago
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    us dis meth eteics?

  6. Jhannybean
    • one year ago
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    To fin the inverse first replace \(f(x) \rightarrow y\) Switch \(y\) and \(x\) Solve for \(y\) Relabel it \(g(x)\)

  7. anonymous
    • one year ago
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    i unle no sciunce

  8. anonymous
    • one year ago
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    i tink ut is C

  9. anonymous
    • one year ago
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    us ut C?

  10. anonymous
    • one year ago
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    i already did the first part

  11. anonymous
    • one year ago
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    |dw:1443800485942:dw|

  12. anonymous
    • one year ago
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    det du ansa

  13. anonymous
    • one year ago
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    if ur not going to help then can u please leave this question

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  14. anonymous
    • one year ago
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    i um trina hulp wit ur questun

  15. anonymous
    • one year ago
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    ok then how would i do this?

  16. anonymous
    • one year ago
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    i juzt guv u de ansa

  17. anonymous
    • one year ago
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    |dw:1443800590243:dw|

  18. anonymous
    • one year ago
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    dut us de ansa

  19. anonymous
    • one year ago
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    @Nnesha

  20. anonymous
    • one year ago
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    i jus guv u de ansa

  21. Jhannybean
    • one year ago
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    Alright, you've found your inverse, now you're looking for \(f(g(x))\) and \(g(f(x))\)

  22. anonymous
    • one year ago
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    so would i use (fog) or (gof)

  23. Jhannybean
    • one year ago
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    Yep

  24. anonymous
    • one year ago
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    which one woudl i use?

  25. Jhannybean
    • one year ago
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    \[f(g(x)) = f\left(4x-8\right) =\frac{1}{4}(4x-8)+2 =~?\] \[g(f(x)) = g\left(\frac{1}{4}x+2\right) =4\left(\frac{1}{4}x+2\right)+2=~? \]

  26. anonymous
    • one year ago
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    ok so do it wiht both of them irhgt?

  27. Jhannybean
    • one year ago
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    Yep, we're proving their inverses of one another.

  28. anonymous
    • one year ago
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    okie thanks :)

  29. Jhannybean
    • one year ago
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    You got it?

  30. anonymous
    • one year ago
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    um i have a problem when i went to do the (gof)(x) i got x+10 as the answer

  31. anonymous
    • one year ago
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    @Jhannybean @Nnesha @paki

  32. anonymous
    • one year ago
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    @ParthKohli

  33. anonymous
    • one year ago
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    @pooja195

  34. anonymous
    • one year ago
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    i am really not sure... sorry :\

  35. anonymous
    • one year ago
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    thats ok @Nnesha @Jhannybean do yall know what i did wrong? can you help?

  36. anonymous
    • one year ago
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  37. Jhannybean
    • one year ago
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    Let's work both of them out.

  38. anonymous
    • one year ago
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    ok

  39. Jhannybean
    • one year ago
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    \[f(g(x)) = f\left(4x-8\right) =\frac{1}{4}(4x-8)+2 =\frac{1}{4}(4x) - \frac{1}{4}(8)+2 = x-2+2 = \color{red}{x}\]

  40. anonymous
    • one year ago
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    i already got that i just need help on the (gof)(x) one

  41. Jhannybean
    • one year ago
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    \[g(f(x)) = g\left(\frac{1}{4}x+2\right) =4\left(\frac{1}{4}x+2\right)\color{blue}{-8} =4\left(\frac{1}{4}x\right) +4(2)\color{blue}{-8} = x \color{red}{+8-8} = x\]

  42. Jhannybean
    • one year ago
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    It was a typo. I was looking at \(f(x)\) and wrote in a \(+2\) instead of a \(-8\) .

  43. anonymous
    • one year ago
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    oh ok thanks

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is replying to Can someone tell me what button the professor is hitting...

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