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Faolan

  • one year ago

CAN SOMEONE HELP ME?!?! Use the Remainder Theorem to completely factor p(x) = x^3 + 7x^2 + 11x + 5

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  1. Faolan
    • one year ago
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    I don't get what to do..................................................................................................... :'(

  2. ParthKohli
    • one year ago
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    -1 works as a root. \(x+1\) is a factor.

  3. Faolan
    • one year ago
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    so...what do i do?

  4. Faolan
    • one year ago
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    how am i supposed to find the factor?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!!??!

  5. freckles
    • one year ago
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    divide p(x) by (x+1)

  6. Faolan
    • one year ago
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    so..... x+1/x^3 + 7x^2 + 11x + 5

  7. Faolan
    • one year ago
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    @freckles

  8. Faolan
    • one year ago
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    do i divide those?

  9. Faolan
    • one year ago
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    thx for the help..... :'(

  10. freckles
    • one year ago
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    well you divide p(x) by (x+1) not (x+1) by p(x) just like you know 2 is a factor of 6 and you can find another factor of 6 by dividing 6 by 2

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