CAN SOMEONE HELP ME?!?! Use the Remainder Theorem to completely factor p(x) = x^3 + 7x^2 + 11x + 5

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CAN SOMEONE HELP ME?!?! Use the Remainder Theorem to completely factor p(x) = x^3 + 7x^2 + 11x + 5

Mathematics
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I don't get what to do..................................................................................................... :'(
-1 works as a root. \(x+1\) is a factor.
so...what do i do?

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how am i supposed to find the factor?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!!??!
divide p(x) by (x+1)
so..... x+1/x^3 + 7x^2 + 11x + 5
do i divide those?
thx for the help..... :'(
well you divide p(x) by (x+1) not (x+1) by p(x) just like you know 2 is a factor of 6 and you can find another factor of 6 by dividing 6 by 2

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