help :)

- anonymous

help :)

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- anonymous

##### 1 Attachment

- M_M13

what's your question? :)

- anonymous

@Michele_Laino

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## More answers

- Michele_Laino

we have:
3/2= 1.5, and 3/4 = 0.75

- anonymous

so c!

- Michele_Laino

correct!

- anonymous

next!

- anonymous

Peter earned $180 working at a store during the summer months. He bought 4 books worth $12 each from his earnings at the store. How much money was left after he bought the books?
$33
$42
$132
$228

- Michele_Laino

the remaining money is: \(180-48=...?\)

- Michele_Laino

since he spent \(12 \cdot 4=48$\)

- anonymous

132

- Michele_Laino

ok!

- anonymous

c?

- Michele_Laino

of course!

- anonymous

ok next! :)

- anonymous

Ada is showing her work in simplifying (5.9 – 1.8) – 6.2 + 4.1. In which step did Ada make an error?
Step 1: (5.9 – 1.8) – 6.2 + 4.1
Step 2: 5.9 + (–1.8 – 6.2) + 4.1 (associative property)
Step 3: 5.9 – 8 + 4.1
Step 4: 5.9 + 4.1 – 8 (associative property)
Step 5: 10 – 8 = 2
Step 2; she wrote associative instead of commutative
Step 2; she wrote associative instead of distributive
Step 4; she wrote associative instead of commutative
Step 4; she wrote associative instead of distributive

- Michele_Laino

when I swap two operands, I'm applying the commutative property

- anonymous

A?

- Michele_Laino

I think A is a wrong option

- anonymous

c?

- Michele_Laino

correct!

- anonymous

next!

- Michele_Laino

next please

- anonymous

##### 1 Attachment

- anonymous

A?

- Michele_Laino

please wait a moment, I have to answer to my phone

- anonymous

ok :)

- Michele_Laino

ok! I'm here

- Michele_Laino

we can write this:
\[2\frac{1}{9} - \left( { - 4\frac{1}{3}} \right) = - \frac{{19}}{9} + \frac{{13}}{3} = \frac{{ - 19 + 39}}{9} = ...?\]

- anonymous

20

- anonymous

20 / 9 ?

- Michele_Laino

oops...
\[ - 2\frac{1}{9} - \left( { - 4\frac{1}{3}} \right) = - \frac{{19}}{9} + \frac{{13}}{3} = \frac{{ - 19 + 39}}{9} = ...?\]

- Michele_Laino

correct!

- Michele_Laino

now, we have:
\[20:9 = 2 \cdot 9 + 2\]

- anonymous

20

- Michele_Laino

being:
\[20:9 = 2 \cdot 9 + 2\]
what is the right option?

- anonymous

A?

- Michele_Laino

correct!

- Michele_Laino

oops.. I have made an error, the right expression is:
\[20 = 2 \cdot 9 + 2\]

- anonymous

right A?

- Michele_Laino

yes!

- anonymous

ok next! :)

- anonymous

What is the sign of the product (–5)(–3)(–8)(–6)?
Positive, because the products (–5)(–3) and (–8)(–6) are negative, and the product of two negative numbers is positive
Positive, because the products (–5)(–3) and (–8)(–6) are positive, and the product of two positive numbers is positive
Negative, because the products (–5)(–3) and (–8)(–6) are negative, and the product of two negative numbers is negative
Negative, because the products (–5)(–3) and (–8)(–6) are positive, and the product of two positive numbers is negative

- Michele_Laino

hint:
you have to apply the sign rule:
\(- \cdot -=+\)

- Michele_Laino

and:
\( + \cdot +=+\)

- anonymous

b?

- Michele_Laino

correct!

- anonymous

Sally swam a total distance of 3 and 1 over 2 miles during the months of November and December. If Sally only swam 1 over 4 of a mile every day, which expression shows the number of days she went swimming?
3 and 1 over 2 ⋅ 1 over 4
3 and 1 over 2 ÷ 1 over 4
3 and 1 over 2 + 1 over 4
3 and 1 over 2 – 1 over 4

- Michele_Laino

we have to divide the total distance by the unit distance

- anonymous

b?

- Michele_Laino

correct!

- anonymous

Michelle bought 2 tickets to a zoo. After she bought the tickets, her account balance showed a change of –$33.04. What would have been the change to Michelle's account balance had she only bought 1 ticket to the zoo?
–$16.52
$16.52
$16.50
–$16.50

- Michele_Laino

since two ticket cost 33.04$ then one ticket costs: \(33.04: 2=...?\)

- Michele_Laino

tickets*

- anonymous

16.52

- Michele_Laino

correct!

- anonymous

next!

- anonymous

wait is it A?

- Michele_Laino

yes!

- anonymous

oh ok next! :)

- anonymous

Which of the following describes a situation in which the total distance a hockey player travels is 0 meter from his starting point?
The player skates 0 meter forward and then skates 8 meters in the opposite direction.
The player skates 9 meters forward and then skates 8 meters in the opposite direction.
The player skates 12 meters forward and then skates 0 meter in the opposite direction.
The player skates 12 meters forward and then skates 12 meters in the opposite direction.

- anonymous

d?

- Michele_Laino

yes!

- anonymous

Which of the following correctly uses absolute value to show the distance between –60 and 11?
|–60 – 11| = |–71| = –71 units
|–60 + 11| = |–49| = 49 units
|–60 + 11| = |–49| = –49 units
|–60 – 11| = |–71| = 71 units

- Michele_Laino

total distance is given by the absolute value of the difference between your values

- anonymous

d?

- Michele_Laino

yes!

- anonymous

Jinni opened a bank account. She deposited $87.60 into her account every month for 10 months. She used $25.60 every month to pay for music classes. After 10 months, she used 1 over 4 of the total money left in her account to go to a summer camp for musicians. What is the total amount of money Jinni spent to go to the summer camp?
$64.00
$88.00
$155.00
$620.00

- Michele_Laino

deposited money is \(87.60 \cdot 10=...?\)

- anonymous

876

- Michele_Laino

the spent money is: \(25.6 \cdot 10 =...? \)

- anonymous

256

- Michele_Laino

the remaining money is: \(876-256=...? \)

- anonymous

620

- Michele_Laino

and 1 over 4 of 620 is: \(620:4=...?\)

- anonymous

ok so d?

- Michele_Laino

please what is \(620 :4 =...? \)

- anonymous

620

- Michele_Laino

I got \(620 :4 = 155 \), am I right?

- anonymous

yes

- Michele_Laino

so, what is the right option?

- anonymous

c?

- Michele_Laino

correct!

- anonymous

next! :)

- anonymous

##### 1 Attachment

- Michele_Laino

what is:
\[\frac{{36}}{2} = ...?\]

- Michele_Laino

\(36:2=...?\)

- anonymous

18

- Michele_Laino

and \(54:3=...?\)

- anonymous

18

- Michele_Laino

and \(90:5=...?\)

- anonymous

every single one is 18 :)

- Michele_Laino

yes!

- anonymous

The regular price of a hooded jacket is $25.75. During a sale, the jacket was marked as 20% off. What was the approximate price of the jacket during the sale?
$5.15
$20.60
$21.62
$23.75

- Michele_Laino

the discount is: \(25.75 \cdot 0.2=...?\)

- anonymous

A?

- Michele_Laino

no, it is the first step

- anonymous

oh okay 5.15

- Michele_Laino

ok!
So the requested price is: \(25.75-5.15=...?\)

- anonymous

20.6

- Michele_Laino

correct!

- anonymous

Jade measured the height of an art frame as 5.23 feet, but the actual height was 6 feet. What is the percent of error in Jade's measurement?
12.83%
13.55%
14.72%
15.55%

- Michele_Laino

the requested percentage error is given by this computation:
\[\frac{{6 - 5.23}}{6} \cdot 100 = ...?\]

- anonymous

12.833333

- Michele_Laino

correct! \(12.83 \%\)

- anonymous

The price of apples at a farm is $1.99 per pound. Which equation can be used to determine c, the total price of n pounds of apples?
c = 1.99 over n
c = 1.99n
c = 1.99 + n
c = 1.99 − n

- Michele_Laino

if 1 pound costs \( 1.99 \$ \) then 2 pounds cost \( 1.99 \cdot 2\),
3 pounds cost \( 1.99 \cdot 3\), four pounds cost \( 1.99 \cdot 4\)

- anonymous

b?

- Michele_Laino

yes!

- Michele_Laino

please, now I have to go to have my dinner, see you tomorrow :)

- anonymous

wait... i only have 5 more quick questions.. please help :)

- Michele_Laino

only one question, since I have to go to have my dinner

- anonymous

Lisa surveyed 60 students at her school and found that 0.85 of the students she surveyed said their favorite class is math. Another 15% of the students she surveyed reported that their favorite class is science. How many more students in the survey prefer math over science?
9
15
35
42

- Michele_Laino

students who prefer class of math are: \(60 \cdot 0.85=...?\)

- anonymous

51

- Michele_Laino

students who prefer class of science are: \(60 \cdot 0.15=...?\)

- anonymous

9

- Michele_Laino

and the requested difference is: \(51-9=...?\)

- anonymous

42

- Michele_Laino

correct!
ok! see you tomorrow :)

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