## anonymous one year ago help :)

1. anonymous

2. M_M13

3. anonymous

@Michele_Laino

4. Michele_Laino

we have: 3/2= 1.5, and 3/4 = 0.75

5. anonymous

so c!

6. Michele_Laino

correct!

7. anonymous

next!

8. anonymous

Peter earned $180 working at a store during the summer months. He bought 4 books worth$12 each from his earnings at the store. How much money was left after he bought the books? $33$42 $132$228

9. Michele_Laino

the remaining money is: $$180-48=...?$$

10. Michele_Laino

since he spent $$12 \cdot 4=48$$

11. anonymous

132

12. Michele_Laino

ok!

13. anonymous

c?

14. Michele_Laino

of course!

15. anonymous

ok next! :)

16. anonymous

Ada is showing her work in simplifying (5.9 – 1.8) – 6.2 + 4.1. In which step did Ada make an error? Step 1: (5.9 – 1.8) – 6.2 + 4.1 Step 2: 5.9 + (–1.8 – 6.2) + 4.1 (associative property) Step 3: 5.9 – 8 + 4.1 Step 4: 5.9 + 4.1 – 8 (associative property) Step 5: 10 – 8 = 2 Step 2; she wrote associative instead of commutative Step 2; she wrote associative instead of distributive Step 4; she wrote associative instead of commutative Step 4; she wrote associative instead of distributive

17. Michele_Laino

when I swap two operands, I'm applying the commutative property

18. anonymous

A?

19. Michele_Laino

I think A is a wrong option

20. anonymous

c?

21. Michele_Laino

correct!

22. anonymous

next!

23. Michele_Laino

24. anonymous

25. anonymous

A?

26. Michele_Laino

27. anonymous

ok :)

28. Michele_Laino

ok! I'm here

29. Michele_Laino

we can write this: $2\frac{1}{9} - \left( { - 4\frac{1}{3}} \right) = - \frac{{19}}{9} + \frac{{13}}{3} = \frac{{ - 19 + 39}}{9} = ...?$

30. anonymous

20

31. anonymous

20 / 9 ?

32. Michele_Laino

oops... $- 2\frac{1}{9} - \left( { - 4\frac{1}{3}} \right) = - \frac{{19}}{9} + \frac{{13}}{3} = \frac{{ - 19 + 39}}{9} = ...?$

33. Michele_Laino

correct!

34. Michele_Laino

now, we have: $20:9 = 2 \cdot 9 + 2$

35. anonymous

20

36. Michele_Laino

being: $20:9 = 2 \cdot 9 + 2$ what is the right option?

37. anonymous

A?

38. Michele_Laino

correct!

39. Michele_Laino

oops.. I have made an error, the right expression is: $20 = 2 \cdot 9 + 2$

40. anonymous

right A?

41. Michele_Laino

yes!

42. anonymous

ok next! :)

43. anonymous

What is the sign of the product (–5)(–3)(–8)(–6)? Positive, because the products (–5)(–3) and (–8)(–6) are negative, and the product of two negative numbers is positive Positive, because the products (–5)(–3) and (–8)(–6) are positive, and the product of two positive numbers is positive Negative, because the products (–5)(–3) and (–8)(–6) are negative, and the product of two negative numbers is negative Negative, because the products (–5)(–3) and (–8)(–6) are positive, and the product of two positive numbers is negative

44. Michele_Laino

hint: you have to apply the sign rule: $$- \cdot -=+$$

45. Michele_Laino

and: $$+ \cdot +=+$$

46. anonymous

b?

47. Michele_Laino

correct!

48. anonymous

Sally swam a total distance of 3 and 1 over 2 miles during the months of November and December. If Sally only swam 1 over 4 of a mile every day, which expression shows the number of days she went swimming? 3 and 1 over 2 ⋅ 1 over 4 3 and 1 over 2 ÷ 1 over 4 3 and 1 over 2 + 1 over 4 3 and 1 over 2 – 1 over 4

49. Michele_Laino

we have to divide the total distance by the unit distance

50. anonymous

b?

51. Michele_Laino

correct!

52. anonymous

Michelle bought 2 tickets to a zoo. After she bought the tickets, her account balance showed a change of –$33.04. What would have been the change to Michelle's account balance had she only bought 1 ticket to the zoo? –$16.52 $16.52$16.50 –$16.50 53. Michele_Laino since two ticket cost 33.04$ then one ticket costs: $$33.04: 2=...?$$

54. Michele_Laino

tickets*

55. anonymous

16.52

56. Michele_Laino

correct!

57. anonymous

next!

58. anonymous

wait is it A?

59. Michele_Laino

yes!

60. anonymous

oh ok next! :)

61. anonymous

Which of the following describes a situation in which the total distance a hockey player travels is 0 meter from his starting point? The player skates 0 meter forward and then skates 8 meters in the opposite direction. The player skates 9 meters forward and then skates 8 meters in the opposite direction. The player skates 12 meters forward and then skates 0 meter in the opposite direction. The player skates 12 meters forward and then skates 12 meters in the opposite direction.

62. anonymous

d?

63. Michele_Laino

yes!

64. anonymous

Which of the following correctly uses absolute value to show the distance between –60 and 11? |–60 – 11| = |–71| = –71 units |–60 + 11| = |–49| = 49 units |–60 + 11| = |–49| = –49 units |–60 – 11| = |–71| = 71 units

65. Michele_Laino

total distance is given by the absolute value of the difference between your values

66. anonymous

d?

67. Michele_Laino

yes!

68. anonymous

Jinni opened a bank account. She deposited $87.60 into her account every month for 10 months. She used$25.60 every month to pay for music classes. After 10 months, she used 1 over 4 of the total money left in her account to go to a summer camp for musicians. What is the total amount of money Jinni spent to go to the summer camp? $64.00$88.00 $155.00$620.00

69. Michele_Laino

deposited money is $$87.60 \cdot 10=...?$$

70. anonymous

876

71. Michele_Laino

the spent money is: $$25.6 \cdot 10 =...?$$

72. anonymous

256

73. Michele_Laino

the remaining money is: $$876-256=...?$$

74. anonymous

620

75. Michele_Laino

and 1 over 4 of 620 is: $$620:4=...?$$

76. anonymous

ok so d?

77. Michele_Laino

please what is $$620 :4 =...?$$

78. anonymous

620

79. Michele_Laino

I got $$620 :4 = 155$$, am I right?

80. anonymous

yes

81. Michele_Laino

so, what is the right option?

82. anonymous

c?

83. Michele_Laino

correct!

84. anonymous

next! :)

85. anonymous

86. Michele_Laino

what is: $\frac{{36}}{2} = ...?$

87. Michele_Laino

$$36:2=...?$$

88. anonymous

18

89. Michele_Laino

and $$54:3=...?$$

90. anonymous

18

91. Michele_Laino

and $$90:5=...?$$

92. anonymous

every single one is 18 :)

93. Michele_Laino

yes!

94. anonymous

The regular price of a hooded jacket is $25.75. During a sale, the jacket was marked as 20% off. What was the approximate price of the jacket during the sale?$5.15 $20.60$21.62 $23.75 95. Michele_Laino the discount is: $$25.75 \cdot 0.2=...?$$ 96. anonymous A? 97. Michele_Laino no, it is the first step 98. anonymous oh okay 5.15 99. Michele_Laino ok! So the requested price is: $$25.75-5.15=...?$$ 100. anonymous 20.6 101. Michele_Laino correct! 102. anonymous Jade measured the height of an art frame as 5.23 feet, but the actual height was 6 feet. What is the percent of error in Jade's measurement? 12.83% 13.55% 14.72% 15.55% 103. Michele_Laino the requested percentage error is given by this computation: $\frac{{6 - 5.23}}{6} \cdot 100 = ...?$ 104. anonymous 12.833333 105. Michele_Laino correct! $$12.83 \%$$ 106. anonymous The price of apples at a farm is$1.99 per pound. Which equation can be used to determine c, the total price of n pounds of apples? c = 1.99 over n c = 1.99n c = 1.99 + n c = 1.99 − n

107. Michele_Laino

if 1 pound costs $$1.99 \$$ then 2 pounds cost $$1.99 \cdot 2$$, 3 pounds cost $$1.99 \cdot 3$$, four pounds cost $$1.99 \cdot 4$$

108. anonymous

b?

109. Michele_Laino

yes!

110. Michele_Laino

please, now I have to go to have my dinner, see you tomorrow :)

111. anonymous

112. Michele_Laino

only one question, since I have to go to have my dinner

113. anonymous

Lisa surveyed 60 students at her school and found that 0.85 of the students she surveyed said their favorite class is math. Another 15% of the students she surveyed reported that their favorite class is science. How many more students in the survey prefer math over science? 9 15 35 42

114. Michele_Laino

students who prefer class of math are: $$60 \cdot 0.85=...?$$

115. anonymous

51

116. Michele_Laino

students who prefer class of science are: $$60 \cdot 0.15=...?$$

117. anonymous

9

118. Michele_Laino

and the requested difference is: $$51-9=...?$$

119. anonymous

42

120. Michele_Laino

correct! ok! see you tomorrow :)