anonymous
  • anonymous
Will give medal for help
Algebra
katieb
  • katieb
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anonymous
  • anonymous
What is the average rate of change from x = –4 to x = 1? –3 –1 0 1
anonymous
  • anonymous
1 Attachment
Jhannybean
  • Jhannybean
Average rate of change = \(\dfrac{f(x)-f(a)}{x-a}\)

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Jhannybean
  • Jhannybean
So your function is shifted to the left an its vertex is at (-1,5) How can we write that?
Jhannybean
  • Jhannybean
This might help.
anonymous
  • anonymous
so -4-(-1) 1-5
anonymous
  • anonymous
is that right ^^^^^
anonymous
  • anonymous
you there?
Jhannybean
  • Jhannybean
No that's not correct.
anonymous
  • anonymous
what did i do wrong?
Jhannybean
  • Jhannybean
We need to find our function first.
Jhannybean
  • Jhannybean
So if your graph is shifted 1 unit to the left and 5 units down, then you would write it as \(f(x) = (x\color{red}{+}1)^2\color{red}{-5}\)
Jhannybean
  • Jhannybean
Do you see what I mean?
anonymous
  • anonymous
kind of
anonymous
  • anonymous
mathstudent55
  • mathstudent55
The average change form x = a to x = b is \(\dfrac{f(b) - f(a)}{b - a}\)
mathstudent55
  • mathstudent55
You want the average change from x = -4 to x = 1. It is important to keep the order in m ind. You don't want the average change from x = 1 to x = -4.
anonymous
  • anonymous
1 right
mathstudent55
  • mathstudent55
Find f(-4) and f(1). You can do this by looking in the graph. What is the y-coordinate where x = -4? What is the y-coordinate where x = 1?
anonymous
  • anonymous
y= 1 then right
mathstudent55
  • mathstudent55
In your case, a = -4, and b = 1, so From the graph: f(-4) = 4 f(1) = -1 \(\dfrac{f(1) - f(-4)}{1 - (-4)}\) \(=\dfrac{-1 - 4}{1 + 4}\)

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