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anonymous
 one year ago
Will give medal for help
anonymous
 one year ago
Will give medal for help

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the average rate of change from x = –4 to x = 1? –3 –1 0 1

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.1Average rate of change = \(\dfrac{f(x)f(a)}{xa}\)

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.1So your function is shifted to the left an its vertex is at (1,5) How can we write that?

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.1No that's not correct.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what did i do wrong?

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.1We need to find our function first.

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.1So if your graph is shifted 1 unit to the left and 5 units down, then you would write it as \(f(x) = (x\color{red}{+}1)^2\color{red}{5}\)

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.1Do you see what I mean?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0The average change form x = a to x = b is \(\dfrac{f(b)  f(a)}{b  a}\)

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0You want the average change from x = 4 to x = 1. It is important to keep the order in m ind. You don't want the average change from x = 1 to x = 4.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0Find f(4) and f(1). You can do this by looking in the graph. What is the ycoordinate where x = 4? What is the ycoordinate where x = 1?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0In your case, a = 4, and b = 1, so From the graph: f(4) = 4 f(1) = 1 \(\dfrac{f(1)  f(4)}{1  (4)}\) \(=\dfrac{1  4}{1 + 4}\)
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