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The vertex is (4,1)

right

what are the next steps?

alright and bec a is negative in the question so we would get max point (graph opens down)

so max would be at ((4,1) |dw:1443814926678:dw|

now find x intercept

hmm highest degree is 2 so you should get 2 xintercepts
4 isn't correct

okay, (9,7)

hmm how did you get that ?

I graphed it on my calculator

hmm make sure you typed the correct equation

Alright, I got x=0 and y=-63

yeah that's y-intercept
now substitute y for 0 to find x-intercept

let me know if u don't know how to solve for x

(0,-1)

help

alright wait a sec

\[\huge\rm 0=-4(x-4)^2+1\] do you know the quadratic formula ?

(x-4)^2 is same as (x-4)(x-4) foil it

familiar with the foil method ?

hmmm better use calculator instead google
i didn't get 16

make sure you are looking at the right question

(0,16)

i have no idea how u got that please show some work
we need x intercepts when y =0

-sighs- I typed it in my calculator. (x-4)^2
and graphed, it showed x=0 and y=16

hmm well ur equations is -4(x-4)^2 +1
that's what u should type into the calculator

lots of step lol

steps*

well* ...

Alright, I typed it in.
Graphed.
X=0

lol i was about to post ur question on others thread :D

I'm sorry, I am not that good at math, I'm barely on an intermediate level.

no i have so man tabs open so that's why

many*

do you understand that ?

don't need to find x-intercepts just substitute x for the points in the table that's it

Okay

vertex is max point min = minimum
max = maximum |dw:1443820566646:dw|

|dw:1443820718145:dw|
if the vertex is at (4,1) that would be the maxx point

|dw:1443820778704:dw| use this table
substitute x for its value from the table then solve for y