Please help

- shaleiah

Please help

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- katieb

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- shaleiah

@Nnesha Did I graph these 3 points, right?

- Nnesha

hmm \[\huge\rm y=a(x-h)^2+k\] vertex form of parabola where (h,k) is the vertex point
and find x and y intercepts

- Nnesha

x-intercept is a point where line intersect x-axis when y=0 so substitute y for 0 to find x intercept
y-intercept is a point where line intersect y-axis when x=0 so substitute x for y to find y-intercept

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## More answers

- shaleiah

The vertex is (4,1)

- Nnesha

right

- shaleiah

what are the next steps?

- Nnesha

alright and bec a is negative in the question so we would get max point (graph opens down)

- Nnesha

so max would be at ((4,1) |dw:1443814926678:dw|

- Nnesha

now find x intercept

- Nnesha

hmm highest degree is 2 so you should get 2 xintercepts
4 isn't correct

- shaleiah

okay, (9,7)

- Nnesha

hmm how did you get that ?

- shaleiah

I graphed it on my calculator

- Nnesha

hmm make sure you typed the correct equation

- shaleiah

Alright, I got x=0 and y=-63

- Nnesha

yeah that's y-intercept
now substitute y for 0 to find x-intercept

- Nnesha

let me know if u don't know how to solve for x

- shaleiah

(0,-1)

- shaleiah

help

- Nnesha

alright wait a sec

- Nnesha

\[\huge\rm 0=-4(x-4)^2+1\] do you know the quadratic formula ?

- Nnesha

(x-4)^2 is same as (x-4)(x-4) foil it

- Nnesha

familiar with the foil method ?

- Nnesha

hmmm better use calculator instead google
i didn't get 16

- Nnesha

make sure you are looking at the right question

- shaleiah

(0,16)

- Nnesha

i have no idea how u got that please show some work
we need x intercepts when y =0

- shaleiah

-sighs- I typed it in my calculator. (x-4)^2
and graphed, it showed x=0 and y=16

- Nnesha

hmm well ur equations is -4(x-4)^2 +1
that's what u should type into the calculator

- shaleiah

lots of step lol

- shaleiah

steps*

- Nnesha

will if you want to solve by hand to find x-itnercepts then yes there are lots of steps
if you want to use calculator then there are none

- Nnesha

well* ...

- shaleiah

Alright, I typed it in.
Graphed.
X=0

- Nnesha

lol i was about to post ur question on others thread :D

- shaleiah

I'm sorry, I am not that good at math, I'm barely on an intermediate level.

- Nnesha

or here is another way to graph
x-coordinate of vertex is 4 right
so draw a table |dw:1443819080897:dw|
now substitute those points to find y coordinate

- Nnesha

no i have so man tabs open so that's why

- Nnesha

many*

- Nnesha

do you understand that ?

- Nnesha

don't need to find x-intercepts just substitute x for the points in the table that's it

- shaleiah

Okay

- shaleiah

@Nnesha

- Nnesha

vertex is max point min = minimum
max = maximum |dw:1443820566646:dw|

- Nnesha

|dw:1443820718145:dw|
if the vertex is at (4,1) that would be the maxx point

- Nnesha

|dw:1443820739973:dw| this point should be the max
that's why to find other two points
we should go up 2 and down 4 from the x-coordinate of the vertex

- Nnesha

|dw:1443820778704:dw| use this table
substitute x for its value from the table then solve for y