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anonymous

  • one year ago

Please help Sketch the graph of a function g for which g(0)=g(2)=g(4)=0, g'(1)=g'(3)=0, g'(0)=g'(4)=1, g'(2)= -1, limit as x approaches infinity g(x)= infinity, limit as x approaches negative infinity g(x)= negative infinity.

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  1. Loser66
    • one year ago
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    |dw:1443816012372:dw|

  2. Loser66
    • one year ago
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    g'(1) =g'(3) =0 means g get max or minimum at 1 and 3

  3. Loser66
    • one year ago
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    |dw:1443816120746:dw|

  4. Loser66
    • one year ago
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    g'(0) =g'(4) =1 means the slope of g is positive at 0 and 4, then the graph is ok so far. that is |dw:1443816260121:dw|

  5. Loser66
    • one year ago
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    g'(2) =-1 is negative, also check. |dw:1443816323542:dw|

  6. Loser66
    • one year ago
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    x approaches infinitive, g approaches infinitive, check |dw:1443816398643:dw|

  7. Loser66
    • one year ago
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    same as other side, x decreases, g decreases, |dw:1443816462084:dw|

  8. Loser66
    • one year ago
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    That is the way you solve this problem.

  9. anonymous
    • one year ago
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    It also says that it's continuous on its domain of (-5,5) so how can I show this?

  10. Loser66
    • one year ago
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    At the beginning, if you go backward, like |dw:1443816511406:dw|

  11. Loser66
    • one year ago
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    g'(0) =g'(4) =1, it doesn't satisfy if you draw the slopes out|dw:1443816611171:dw|

  12. Loser66
    • one year ago
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    about continuous, you just show |dw:1443816667411:dw|

  13. anonymous
    • one year ago
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    Okay thanks so much

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