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anonymous
 one year ago
Please help
Sketch the graph of a function g for which
g(0)=g(2)=g(4)=0, g'(1)=g'(3)=0, g'(0)=g'(4)=1, g'(2)= 1, limit as x approaches infinity g(x)= infinity, limit as x approaches negative infinity g(x)= negative infinity.
anonymous
 one year ago
Please help Sketch the graph of a function g for which g(0)=g(2)=g(4)=0, g'(1)=g'(3)=0, g'(0)=g'(4)=1, g'(2)= 1, limit as x approaches infinity g(x)= infinity, limit as x approaches negative infinity g(x)= negative infinity.

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Loser66
 one year ago
Best ResponseYou've already chosen the best response.1g'(1) =g'(3) =0 means g get max or minimum at 1 and 3

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1g'(0) =g'(4) =1 means the slope of g is positive at 0 and 4, then the graph is ok so far. that is dw:1443816260121:dw

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1g'(2) =1 is negative, also check. dw:1443816323542:dw

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1x approaches infinitive, g approaches infinitive, check dw:1443816398643:dw

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1same as other side, x decreases, g decreases, dw:1443816462084:dw

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1That is the way you solve this problem.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It also says that it's continuous on its domain of (5,5) so how can I show this?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1At the beginning, if you go backward, like dw:1443816511406:dw

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1g'(0) =g'(4) =1, it doesn't satisfy if you draw the slopes outdw:1443816611171:dw

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1about continuous, you just show dw:1443816667411:dw
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