mckenzieandjesus
  • mckenzieandjesus
Find a solution to the following system of equations. mc002-1.jpg mc002-2.jpg A. (-8, -15) B. (0,1) C.(-2, -15) D.(2,5)
Algebra
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

mckenzieandjesus
  • mckenzieandjesus
-5x+y=-5 -4x+2y=2 for the images
yolomcswagginsggg
  • yolomcswagginsggg
yolomcswagginsggg
  • yolomcswagginsggg
this guy needs halp ;p

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

yolomcswagginsggg
  • yolomcswagginsggg
haleyelizabeth2017
  • haleyelizabeth2017
Plug in y=5x-5 (-5x+y=-5 add 5x to both sides) for y in the second equation: -4x+2(5x-5)=2 Think you can do that? Then, just plug in the value you get for x into y=5x-5 and solve for y.
mckenzieandjesus
  • mckenzieandjesus
so do i do 5+5 and -5+5?
mckenzieandjesus
  • mckenzieandjesus
5+5=10 -5+5=0
anonymous
  • anonymous
a maybe
haleyelizabeth2017
  • haleyelizabeth2017
no lol...
haleyelizabeth2017
  • haleyelizabeth2017
my apologies, I'm getting help on my own math lol so... -4x+2(5x-5)=2 -4x+10x-10=2 Think you can take it from there?
mckenzieandjesus
  • mckenzieandjesus
i keep getting an answer thats not on my answer choices.. lol
Koikkara
  • Koikkara
\(-5x+y=-5\) \(-4x+2y=2\) change (Multiply with - ) \(+4x-2y=-2\) Then, \(-5x+y=-5\) \(+4x-2y=-2\) solution: \(x-y=7\) option \(D\) \(2-(-5)=7\)
Koikkara
  • Koikkara
@mckenzieandjesus Check it before you copy.
Koikkara
  • Koikkara
\(NOTE:\) It's just a model... i have purposefully done wrong
mckenzieandjesus
  • mckenzieandjesus
huh?
mckenzieandjesus
  • mckenzieandjesus
so option d isnt right?
Koikkara
  • Koikkara
Time up: \(-5x+y=-5\) \(+4x-2y=-2\) Solution: \(-x-y=-7\) substitute, Option D.(2,5) \(2 \) = \(x\) \(5 \) = \(y\) Substitute: \(-x-y=-7\) \(-2-5~=~7\) \(you~are~right~!!\) @mckenzieandjesus
Koikkara
  • Koikkara
\(**error: ~ -2-5~=~-7\)
anonymous
  • anonymous
U ALWAYS HAVE ERRORS \(BANG\)
anonymous
  • anonymous
\(freddy laugh\)
mckenzieandjesus
  • mckenzieandjesus
?
anonymous
  • anonymous
Five Nights At Freddy's never heard of it?

Looking for something else?

Not the answer you are looking for? Search for more explanations.