At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
You could find f'(x). Then find where f'>0 (this is where f is increasing) Then find where f'<0 (this is where f is decreasing)
|dw:1443816836547:dw| Graph comes like this.. lol and Hai...
@haleyelizabeth2017 Which means it's increasing...lol
lol I have to find the intervals...
@haleyelizabeth2017 have you found the critical numbers yet?
No, still working on it.
Do I set f(x) to 0 and solve for x?
To find critical numbers you solve f'(x)=0 for x.
yes derivative of f
do you know any calculus?
or you suppose to graph it in your calculator and say where the function is increasing or decreasing?
I do not know any calculus lol...
Well how do they expect you to answer this? Calculator right?
I think so
|dw:1443817293708:dw| we need to find these numbers a and b
read the function from left to right
the function is rising on (-inf,a) then falling on (a,b) then rising again on (b,inf)
all you have to do now is find those numbers a and b also called the turning points of the function using your calculator
also let me put some numbers on my graph because I don't want you to think that is y=0... |dw:1443817470752:dw| it was just meant to be a rough picture anyways
those equations aren't even that important (talking about the x=0 and the y=2)