## anonymous one year ago Calculus help Find the relative extrema of the function f(x) = x^4 - 32x^2 + 3 I've worked this out on the calculator, but I am unsure how to do on pen and paper. I tried completing the square, but it doesn't seem to come out right. Relative maximum at (0, 3); relative minima at (4, -253), (-4, -253)

1. Vocaloid

take the derivative

2. anonymous

3x^3-64x This doesn't factor evenly

3. anonymous

$f \prime \left( x \right)=4x^3-64x$ $f \prime \left( x \right)=0~gives~4x^3-64x=0$ 4x(x^2-16)=0 x=0,-4,4

4. anonymous

find $f \prime \prime \left( x \right) ~all~three~ points~for~maxima~and~minima.$

5. anonymous

Wow, I missed that one, Thanks

6. Jhannybean

nope this helps too.

7. Jhannybean