Setsuna-Yuregeshi
  • Setsuna-Yuregeshi
The specification for a length x is 43.6 cm with a tolerance of 0.1 cm. Write the specification as an absolute value inequality.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Setsuna-Yuregeshi
  • Setsuna-Yuregeshi
I really need help, but on how to do it. Not just the answer please...
Vocaloid
  • Vocaloid
hint: the absolute value of the difference between x and 43.6 is less than or equal to the tolerance
Setsuna-Yuregeshi
  • Setsuna-Yuregeshi
Um... So |x-43.6|

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Vocaloid
  • Vocaloid
almost. what is the tolerance?
Setsuna-Yuregeshi
  • Setsuna-Yuregeshi
What does tolerance mean?
Setsuna-Yuregeshi
  • Setsuna-Yuregeshi
lol
Setsuna-Yuregeshi
  • Setsuna-Yuregeshi
I don't know :(
Vocaloid
  • Vocaloid
"tolerance of 0.1" means that the value of x will be no more than 43.6 + 0.1, and no less than 43.6 - 0.1 basically, the tolerance gives you an upper bound and a lower bound for the possible x values
Vocaloid
  • Vocaloid
so our inequality is |x - 43.6| <= 0.1
Setsuna-Yuregeshi
  • Setsuna-Yuregeshi
eh?
Setsuna-Yuregeshi
  • Setsuna-Yuregeshi
How come?
Vocaloid
  • Vocaloid
think about what this statement means |x - 43.6| <= 0.1 |x - 43.6| represents the distance between x and 43.6. the inequality means that x will be no more than 0.1 units away from 43.6
Vocaloid
  • Vocaloid
|dw:1443822176291:dw|
Setsuna-Yuregeshi
  • Setsuna-Yuregeshi
Ooh,
Vocaloid
  • Vocaloid
|dw:1443822217532:dw|
Setsuna-Yuregeshi
  • Setsuna-Yuregeshi
because x has to be either 43.6 or .1+ or - 43.6. The tolerance means it has to be in that range??
Setsuna-Yuregeshi
  • Setsuna-Yuregeshi
@Vocaloid
Vocaloid
  • Vocaloid
uh... not quite
Vocaloid
  • Vocaloid
"tolerance of 0.1" means that the maximum value of x is 43.6 + 0.1 = 43.7 the minimum value of x is 43.6 - 0.1 = 43.5 that's why "0.1" is the tolerance value
Setsuna-Yuregeshi
  • Setsuna-Yuregeshi
ooh, ok thanks! @Vocaloid

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