Find the equation of the tangent line to the curve at the given point. y = 5x − 2squarerootx, (1, 3)

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Find the equation of the tangent line to the curve at the given point. y = 5x − 2squarerootx, (1, 3)

Mathematics
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Can you find the first derivative of the function?
@ElfQueen Hello. Are you there?
You may find the first derivative and then find f'(1) which will give you your slope, and then use the following equation \[y-y_1=m(x-x_1)\]

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@Mertsj Sorry. I was making myself dinner. I got 5 - 1over the squareroot x.
That's correct \[f'(x) = 5-\frac{ 1 }{ \sqrt{x} }\] now find f'(1)
4
Yes! So our slope is 4, now we can use the point slope equation and we will have our equation
4x-1
I'm not sure what that means, we just have to use \[y-y_1=m(x-x_1)\] and we are given the point (x1,y1)

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