A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Find the equation of the tangent line to the curve at the given point.
y = 5x − 2squarerootx, (1, 3)
anonymous
 one year ago
Find the equation of the tangent line to the curve at the given point. y = 5x − 2squarerootx, (1, 3)

This Question is Closed

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2Can you find the first derivative of the function?

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2@ElfQueen Hello. Are you there?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You may find the first derivative and then find f'(1) which will give you your slope, and then use the following equation \[yy_1=m(xx_1)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Mertsj Sorry. I was making myself dinner. I got 5  1over the squareroot x.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's correct \[f'(x) = 5\frac{ 1 }{ \sqrt{x} }\] now find f'(1)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes! So our slope is 4, now we can use the point slope equation and we will have our equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm not sure what that means, we just have to use \[yy_1=m(xx_1)\] and we are given the point (x1,y1)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.