## anonymous one year ago Find the equation of the tangent line to the curve at the given point. y = 5x − 2squarerootx, (1, 3)

1. Mertsj

Can you find the first derivative of the function?

2. Mertsj

@ElfQueen Hello. Are you there?

3. anonymous

You may find the first derivative and then find f'(1) which will give you your slope, and then use the following equation $y-y_1=m(x-x_1)$

4. anonymous

@Mertsj Sorry. I was making myself dinner. I got 5 - 1over the squareroot x.

5. anonymous

That's correct $f'(x) = 5-\frac{ 1 }{ \sqrt{x} }$ now find f'(1)

6. anonymous

4

7. anonymous

Yes! So our slope is 4, now we can use the point slope equation and we will have our equation

8. anonymous

4x-1

9. anonymous

I'm not sure what that means, we just have to use $y-y_1=m(x-x_1)$ and we are given the point (x1,y1)