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Please help, I'm stuck!

how can you tell a function from just a relation?
hint: recall your DOMAIN and RANGE sets

Ehhh I need a little more of a description on how to do it, I'm still confused

I get it, so it's B!

It couldn't be A? Because it's only a x-value right? So that'd just leave C and D

That's right. For a the x-value of 1 has an infinite number of y-values. Check the others.

I have a feeling that the answer is D, if that's right could you explain to me why please?

Let's look at D. Are you able to rearrange it to solve for y?

Maybe, 16+4x^2=y?

Not quite\[4x^2 + y^2 = 16\]\[y^2 = 16 - 4x^2\]\[y=\pm \sqrt{16-4x^2}\]Are you able to follow that?

Yeah, so what does this tell us? That there is only a value for the y?

0 I guess? Sorry, I'm just not getting it as quickly as others probably would

You can do this. What's the square root of 16?

Oh that's easy, 4

I think the square root of 16 is -4

Ummmm, no...no it's not...

Must be because (-4)(-4)=16

Maybe 16 has two square roots.

Anyways, yes, it does represent a function

The square root of a number is a number which multiplied by itself, gives you the original number.

@RavenDarkwood200 Me too.

@RavenDarkwood200 Wie kann der Blinde den Blinden führt