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DarkBlueChocobo
 one year ago
Help with trig
DarkBlueChocobo
 one year ago
Help with trig

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DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.1If tan(theta)>0 and sec(theta)<0 then theta is in which quadrant?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4Ever heard of CAST?

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.1But I was thinking if tan = sin/cos then sin and cos were are not negative

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.1or they are both negative or both positive?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4dw:1443835637183:dw It's like a quick way to see where the ratios are positive and negative, A represents all positive in that quadrant, S is sin theta, C is cos theta, and T is tan theta. So they are positive in those quadrants where the letter is, and negative in the rest.

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.1so it would be the 3rd quadrant then?

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.1since Tan is positive in quadrant 3 ?

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.1Well thank you for the new method of solving that. That makes everything a lot more easy

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4It's a pretty handy trick if you don't want to spend a bunch of time on these problems, but know how the ratios work, :)

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.1Explain how the ratios work? I was thinking if tan is > 0 then sin and cos must be positive in order to get out positive

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4I mean ratio as in if you have triangles, because \[\tan \theta = \frac{ y }{ x }\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4\[\sin \theta = \frac{ y }{ r }\] \[\cos \theta = \frac{ x }{ r }\] \[\tan \theta = \frac{ \sin \theta }{ \cos \theta } = \frac{ \frac{ y }{ r } }{ \frac{ x }{ r } } = \frac{ y }{ x }\]

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.1yes but where does that relate to in quadrants?

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.1i understand the unit circle and stuff I just don't get like what that have to deal with finding it like if it was sin>0 and cos<0 Then you could pinpoint that it was in the 2nd quad cause that's where that is true

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4Ok lets look at the quadrants dw:1443836610435:dw negative*negative = + that's why tan theta is positive

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4Does that make sense? Or still a bit confused?

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.1I mean i get that a  *  is a positive. I don't get how it relates to tan though

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.1you are saying if y/x=+yx?

DarkBlueChocobo
 one year ago
Best ResponseYou've already chosen the best response.1I would get why that is positive then nevermind

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4Don't over think, it's not as hard as it seems, remember that these trig functions are all related to right triangles, so that's how we really get these ratios it's just \[r = \sqrt{x^2+y^2}\]
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