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DarkBlueChocobo

  • one year ago

Help with trig

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  1. kawii2004
    • one year ago
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    question?

  2. DarkBlueChocobo
    • one year ago
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    If tan(theta)>0 and sec(theta)<0 then theta is in which quadrant?

  3. Astrophysics
    • one year ago
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    Ever heard of CAST?

  4. DarkBlueChocobo
    • one year ago
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    I have not

  5. DarkBlueChocobo
    • one year ago
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    But I was thinking if tan = sin/cos then sin and cos were are not negative

  6. DarkBlueChocobo
    • one year ago
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    or they are both negative or both positive?

  7. Astrophysics
    • one year ago
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    |dw:1443835637183:dw| It's like a quick way to see where the ratios are positive and negative, A represents all positive in that quadrant, S is sin theta, C is cos theta, and T is tan theta. So they are positive in those quadrants where the letter is, and negative in the rest.

  8. DarkBlueChocobo
    • one year ago
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    so it would be the 3rd quadrant then?

  9. DarkBlueChocobo
    • one year ago
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    since Tan is positive in quadrant 3 ?

  10. Astrophysics
    • one year ago
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    Yes, exactly!

  11. DarkBlueChocobo
    • one year ago
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    Well thank you for the new method of solving that. That makes everything a lot more easy

  12. Astrophysics
    • one year ago
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    It's a pretty handy trick if you don't want to spend a bunch of time on these problems, but know how the ratios work, :)

  13. DarkBlueChocobo
    • one year ago
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    Explain how the ratios work? I was thinking if tan is > 0 then sin and cos must be positive in order to get out positive

  14. Astrophysics
    • one year ago
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    I mean ratio as in if you have triangles, because \[\tan \theta = \frac{ y }{ x }\]

  15. Astrophysics
    • one year ago
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    \[\sin \theta = \frac{ y }{ r }\] \[\cos \theta = \frac{ x }{ r }\] \[\tan \theta = \frac{ \sin \theta }{ \cos \theta } = \frac{ \frac{ y }{ r } }{ \frac{ x }{ r } } = \frac{ y }{ x }\]

  16. DarkBlueChocobo
    • one year ago
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    yes but where does that relate to in quadrants?

  17. DarkBlueChocobo
    • one year ago
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    i understand the unit circle and stuff I just don't get like what that have to deal with finding it like if it was sin>0 and cos<0 Then you could pinpoint that it was in the 2nd quad cause that's where that is true

  18. Astrophysics
    • one year ago
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    Ok lets look at the quadrants |dw:1443836610435:dw| negative*negative = + that's why tan theta is positive

  19. Astrophysics
    • one year ago
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    Does that make sense? Or still a bit confused?

  20. DarkBlueChocobo
    • one year ago
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    I mean i get that a - * - is a positive. I don't get how it relates to tan though

  21. DarkBlueChocobo
    • one year ago
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    oh wait

  22. DarkBlueChocobo
    • one year ago
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    you are saying if -y/-x=+yx?

  23. DarkBlueChocobo
    • one year ago
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    I would get why that is positive then nevermind

  24. Astrophysics
    • one year ago
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    Don't over think, it's not as hard as it seems, remember that these trig functions are all related to right triangles, so that's how we really get these ratios it's just \[r = \sqrt{x^2+y^2}\]

  25. DarkBlueChocobo
    • one year ago
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    Alrights

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