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anonymous

  • one year ago

The point P(9 , 6 ) lies on the curve y = \sqrt{ x } + 3. Let Q be the point (x, \sqrt{ x }+ 3 ). a.) Find the slope of the secant line PQ for the following values of x(Answers here should be correct to at least 6 places after the decimal point.) If x= 9.1, the slope of PQ is: If x= 9.01, the slope of PQ is: If x= 8.9, the slope of PQ is: If x= 8.99, the slope of PQ is: b.) Based on the above results, estimate the slope of the tangent line to the curve at P(9 , 6 ).

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  1. jim_thompson5910
    • one year ago
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    If x= 9.1, then what is the value of y?

  2. anonymous
    • one year ago
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    Of the original function or the derivative?

  3. jim_thompson5910
    • one year ago
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    original function

  4. anonymous
    • one year ago
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    y = \sqrt{ x } + 3 at x=9.1 --> 6.016620626

  5. jim_thompson5910
    • one year ago
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    so we know the point (9.1, 6.016620626) lies on the function curve

  6. jim_thompson5910
    • one year ago
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    P = (9,6) Q = (9.1, 6.016620626) slope of PQ = ??

  7. anonymous
    • one year ago
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    that's what I don't get, I do not know what to do...

  8. jim_thompson5910
    • one year ago
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    you would use the slope formula \[\LARGE m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\]

  9. anonymous
    • one year ago
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    it doesn't work because both x are 9 (we cannot divide by 0)

  10. jim_thompson5910
    • one year ago
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    x1 = 9 x2 = 9.1

  11. jim_thompson5910
    • one year ago
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    so x2 - x1 = 9.1 - 9 = 0.1

  12. anonymous
    • one year ago
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    oh i missed that one, the answer is 0.16620626 ... would that be the answer for the first one?

  13. anonymous
    • one year ago
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    I entered it and it says correct!! thank you! what about b) ?

  14. jim_thompson5910
    • one year ago
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    y1 = 6 y2 = 6.016620626 y2 - y1 = 6.016620626 - 6 = 0.016620626 divide that by 0.1 and you get 0.016620626/0.1 = 0.16620626 so it looks good

  15. jim_thompson5910
    • one year ago
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    repeat the same steps as a) but now use x = 9.01 instead of 9.1

  16. anonymous
    • one year ago
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    I meant the second part of the question

  17. jim_thompson5910
    • one year ago
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    tell me what slopes you get for part a)

  18. anonymous
    • one year ago
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    for every one of them of just the first one?

  19. jim_thompson5910
    • one year ago
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    each one

  20. anonymous
    • one year ago
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    0.16620626 -0.1666203961-0.1671322196-0.1667129887

  21. anonymous
    • one year ago
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    We just do the average?

  22. jim_thompson5910
    • one year ago
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    it's probably not 100% clear but what do you notice that is common to all of these slopes?

  23. anonymous
    • one year ago
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    I tried the average of them and it is correct! Thank you so much, I appreciate it greatly! Could you help me with another quick question?

  24. jim_thompson5910
    • one year ago
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    sure

  25. anonymous
    • one year ago
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    Let f(x) = 3x^{4}-4. (a) Use the limit process to find the slope of the line tangent to the graph of f at x = 3. Slope at x = 3: (I got 324 but i dont know if it is correct) (b) Find an equation of the line tangent to the graph of f at x = 3. Tangent line: y =

  26. anonymous
    • one year ago
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    Do you know how to help me on this one?

  27. triciaal
    • one year ago
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    |dw:1443842056603:dw|

  28. jim_thompson5910
    • one year ago
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    keep following @triciaal steps to find the value of f(3) if x = 3, then y = ??

  29. anonymous
    • one year ago
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    y=239

  30. jim_thompson5910
    • one year ago
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    so we know (3,239) lies on the curve

  31. anonymous
    • one year ago
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    and the slope of 324 was correct?

  32. jim_thompson5910
    • one year ago
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    yes

  33. jim_thompson5910
    • one year ago
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    so you know this line has a slope of 324 and goes through (3,239)

  34. anonymous
    • one year ago
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    so y-y1=m(x-x1) ?

  35. jim_thompson5910
    • one year ago
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    yes

  36. jim_thompson5910
    • one year ago
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    m = 324 (x1,y1) = (3,239)

  37. anonymous
    • one year ago
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    How do you rearrange it so that the equation looks like y= mx+b ??

  38. jim_thompson5910
    • one year ago
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    you just need to solve for y and simplify

  39. anonymous
    • one year ago
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    It worked! I just made a sign mistake at the end.... @jim_thompson5910 I appreciate your help greatly! you saved my grade! @triciaal Thank you also for helping me I appreciate it

  40. jim_thompson5910
    • one year ago
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    you're welcome

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