anonymous
  • anonymous
without graphing, describe the end behavior of the graph of the function f(x)=3x^3
Mathematics
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
jamiebookeater
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
the exponent is odd, hence |dw:1443846217889:dw|
anonymous
  • anonymous
actually that is not complete the exponent is odd AND the leading coefficient is positive (it is 3)
anonymous
  • anonymous
my options look like this\[A s x--->\infty, f(x)--->-\infty\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Astrophysics
  • Astrophysics
Well the greatest degree determines the end behaviour, in your case the degree is 3 (cube) since you have \[y=3x^3 \] and your degree is odd, so we look at the ends of the graph (that's why it's called end behaviour). So if we plug infinity/ - infinity in our function, then f(x) will go to positive infinity and negative infinity
Astrophysics
  • Astrophysics
That's what it means by x-> infinity, so if you plug in larger numbers in the equation you will get a larger number, in this case f(x) = infinity, and since it's odd, if you plug in x-> - infinity then f(x) = - infinity, hope that makes sense!
Astrophysics
  • Astrophysics
So notice odd degrees have two end behaviours

Looking for something else?

Not the answer you are looking for? Search for more explanations.