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anonymous

  • one year ago

Write the point slope form of the equation of the line described through (4,2), and parallel to y=-3/4x-5 I really don't get this can someone help :/

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  1. baru
    • one year ago
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    can you identify the "slope" of the equation y=-3/4x-5?

  2. anonymous
    • one year ago
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    @kaiters1010 what happens to the 5 :?

  3. hartnn
    • one year ago
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    we are not changing the equation y=-3/4x-5, so nothing is gonna happen to 5. we are tying to find the equation of another line parallel to line y=-3/4x-5 so it will be in the form of y=-3/4x+c and we need to find the 'c' we can use the information that 4,2 lies on the line y=-3/4x+c so plug in x =4, y =2 in that 2 =-3/4* 4 +c ! once you get the 'c' , you get the equation

  4. anonymous
    • one year ago
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    and c is gotten like y=x+b correct?

  5. hartnn
    • one year ago
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    you mean y = mx+b ? here m is the slope , b is the y-intercept. we have slope = m= -3/4 here can you try to solve 2 =-3/4* 4 +b to get the value of the y-intercept 'b' ?

  6. anonymous
    • one year ago
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    b=-1

  7. hartnn
    • one year ago
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    how did you get that?? 2 = -(3/4)*4 + b 2 = -3 + b now add 3 on both sides :)

  8. anonymous
    • one year ago
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    Oh which it would be 1 not negative

  9. hartnn
    • one year ago
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    actually, lets do it step wise, 2 = -3 + b 2+3 = -3+3 +b 5 = 0 + b so b= 5 makes sense?

  10. anonymous
    • one year ago
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    Yes It did in the beginning I mixed up on the negative positive bit.

  11. hartnn
    • one year ago
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    so finally, we have the equation as y = -3/4 x + 5 :)

  12. hartnn
    • one year ago
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    ahh, just read the question, we need the equation in "point-slope" form! which is \(y = y_1 = m (x-x_1)\) and the point \(x_1, y_1 = 4,2 \) so the same equation would be \(y - 2 = -(3/4) (x- 4)\)

  13. hartnn
    • one year ago
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    *** \(\Large y \color{red}-y_1 = m (x-x_1)\)

  14. anonymous
    • one year ago
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    So x1 nd y1 is the one i got from the one that is parallel ?

  15. baru
    • one year ago
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    x1 and y1 are the co-ordinates that are given to you : (4,2)

  16. baru
    • one year ago
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    confused?

  17. baru
    • one year ago
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    (4,2) = (x1,y1)

  18. anonymous
    • one year ago
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    then what about y and x I'm getting really confused :/

  19. anonymous
    • one year ago
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    Would the solution be y−2=3/4(x−4)

  20. hartnn
    • one year ago
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    y−2=-3/4(x−4)

  21. anonymous
    • one year ago
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    I see and would that end of the question because it got very simple now

  22. hartnn
    • one year ago
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    yep, thats all we had to do, find the slope, which was -3/4 and plug in the point! x1 = 4, y1 =2

  23. anonymous
    • one year ago
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    So basically the point slope form would be y-2=-3/4(x-4

  24. hartnn
    • one year ago
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    yes

  25. anonymous
    • one year ago
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    Ok I got 3 more questions I'll try to do myself if I have any questions would it be ok to tag you :?

  26. hartnn
    • one year ago
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    sure :)

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