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can you identify the "slope" of the equation y=-3/4x-5?

@kaiters1010 what happens to the 5 :?

and c is gotten like y=x+b correct?

b=-1

how did you get that??
2 = -(3/4)*4 + b
2 = -3 + b
now add 3 on both sides :)

Oh which it would be 1 not negative

actually, lets do it step wise,
2 = -3 + b
2+3 = -3+3 +b
5 = 0 + b
so b= 5
makes sense?

Yes It did in the beginning I mixed up on the negative positive bit.

so finally, we have the equation as
y = -3/4 x + 5 :)

***
\(\Large y \color{red}-y_1 = m (x-x_1)\)

So x1 nd y1 is the one i got from the one that is parallel ?

x1 and y1 are the co-ordinates that are given to you : (4,2)

confused?

(4,2) = (x1,y1)

then what about y and x I'm getting really confused :/

Would the solution be y−2=3/4(x−4)

y−2=-3/4(x−4)

I see and would that end of the question because it got very simple now

yep, thats all we had to do,
find the slope, which was -3/4
and plug in the point!
x1 = 4, y1 =2

So basically the point slope form would be y-2=-3/4(x-4

yes

Ok I got 3 more questions I'll try to do myself if I have any questions would it be ok to tag you :?

sure :)