## Adi3 one year ago Will medal Please help. Sketch the following functions on the same set of axes as y = x^2. In each case, state the coordinates of the vertex. y = -(x-1)^2 + 3

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8. IrishBoy123

|dw:1443858498605:dw|

9. IrishBoy123

|dw:1443858518127:dw|

10. IrishBoy123

ie take it step by step

i didn't get that

13. IrishBoy123

ok late's start with $$y = x^2$$ what does $$y = (x-1)^2$$ look like?

(x-1)(x-1), can't Foil it??

15. IrishBoy123

no need for that whereas y = 0 when x = 0 for $$y = x^2$$, y = 0 when x = 1 for $$y = (x-1)^2$$ it's a shift of the curve, yes?

so it moves one to the right.

17. IrishBoy123

indeed!

18. IrishBoy123

now let's compare $$y = x^2$$ with $$y = x^2 +3$$ that's just another shift

so it moves 3 point up.

20. IrishBoy123

indeed now what about $$y = x^2$$ and $$y = -x^2$$ ??

reflect horizontally????

22. IrishBoy123

yes, you can see it that way. a reflection in the horizontal axis or a 180 rotation. either is good |dw:1443859072630:dw|

23. IrishBoy123

in your case you have all three at once, ie the horizontal and vertical shifts and the reflection $$y = x^2 \rightarrow y = -(x-1)^2 + 3$$

24. IrishBoy123

hence |dw:1443859195875:dw|

thank you. a lot. really needed help!!!!!!!!, thank you mate.

26. IrishBoy123

mp!