## Jhannybean one year ago how would I write the chemical equation when sodium hydroxide is mixed with water reacts with carbon dioxide in the atmosphere to produce carbonic acid?

1. Jhannybean

@Shalante

2. aaronq

I'm thinking this would need at least 2 steps $$\sf NaOH +H_2O+CO_2\rightarrow H_2CO_3+NaOH\rightarrow NaHCO_3+H_2O$$

3. anonymous

I think this requires two steps. So first equation is sodium hydroxide mixed with water Since sodium hydroxide is soluble in water it dissociates into ions. $NaOH(s)+H _{2}O(l)\rightarrow Na ^{+}(aq)+OH ^{-}(aq)+H _{2} O(l)$ It then reacts with carbon dioxide So the 2nd chemical equation is. $Na ^{+}(aq)+OH ^{-}(aq)+H _{2}O(l)+CO _{2} (g)\rightarrow H _{2}CO _{3}(aq)+Na ^{+}(aq)+OH ^{-}(aq)$

4. anonymous

What do you think @Jhannybean ?

5. anonymous

@Photon336 What is your approach to this?

6. Jhannybean

in the last equation you wrote, $$\sf Na ^{+}(aq)+OH ^{-}(aq)+H _{2}O(l)+CO _{2} (g)\rightarrow H _{2}CO _{3}(aq)+Na ^{+}(aq)+OH ^{-}(aq)$$ Can ions really behave that way? :o

7. anonymous

Yes because it is in aqueous solution. Carbonic acid (H2CO3 is the solvent. Na+ and OH- is the solute.

8. Photon336

I agree with your approach @shalante

9. anonymous

Thanks for feedback @Photon336

10. Jhannybean

Oh I see, I wasnt familiar with that method but it makes sense after I looked more into it :D

11. anonymous

What was your attempt on this?

12. Jhannybean

At first I had: $$\sf NaOH + H_2O + CO_2 ~\rightarrow ~ H_2CO_3 + ...$$ Wasn't too sure how to write out the rest... But i understand a little more now

13. aaronq

pshsh taking credit for what i initially wrote lol ..

14. Jhannybean

Hahaaha no I had that written before you wrote it!!!!

15. Jhannybean

I didnt know how else they combined xD

16. anonymous

Not 100% sure. Does it look logical to you?

17. Jhannybean

Yeah, it does indeed.