AaronAndyson
  • AaronAndyson
6.4kJ of energy causes a displacement of 64m in a body in the direction of force in 2.5s.Calculate 1.The force applied. 2.Power in HP. Take 1 HP = 746W
Physics
chestercat
  • chestercat
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AaronAndyson
  • AaronAndyson
TorilovesVampires
  • TorilovesVampires
W = K.E = 6.4 kJ = 6.4 x 103 J W = F.d. cos θ Now the displacement of the body is in the direction of applied force. θ = 0 W = F.d F = W/d = (6.4 x 103 J)/64 m F = 100 N Power P = W/t = (6.4 x 103 J)/(2.5) =16 x 103 W =1.6 x 104 W = (1.6 x 104) / 746 = 0.0021 x 104 H.P. Power P = 21 H.P.
AaronAndyson
  • AaronAndyson
???

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Abhisar
  • Abhisar
Yo, wassup?
AaronAndyson
  • AaronAndyson
I'm confused. Shouldn't the F be 10.3?
Abhisar
  • Abhisar
Work = Force x Displacement and this work done will be equal to energy supplied, Right?
AaronAndyson
  • AaronAndyson
Yes.
Abhisar
  • Abhisar
Let the applied force be F, then 6400 = F x 64. Now you can calculate the force.
AaronAndyson
  • AaronAndyson
100N
Abhisar
  • Abhisar
You got it ;)
AaronAndyson
  • AaronAndyson
And the P?
Abhisar
  • Abhisar
\(\sf Power = \frac{Work/Energy}{Time}\) You know the work, you know the time. Just plug in the values and find power.
AaronAndyson
  • AaronAndyson
64000/25?
AaronAndyson
  • AaronAndyson
2560 W?
Abhisar
  • Abhisar
6.4 KJ = 6400 J
Abhisar
  • Abhisar
Power = 6400/25
AaronAndyson
  • AaronAndyson
Time is 2.5 s not 25s
Abhisar
  • Abhisar
Right, then it's correct!
Abhisar
  • Abhisar
Finally, convert the power into HP. 1 HP =746 Watts.
AaronAndyson
  • AaronAndyson
3.43?
Abhisar
  • Abhisar
That's right!
AaronAndyson
  • AaronAndyson
Thanks @Abhisar and @TorilovesVampires both.
Abhisar
  • Abhisar
pleasure is all mine c:

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