• jarp0120
a reservoir is in the form of a frustrum of a cone with upper base of radius 9 ft and lower base of radius 4ft and altitute of 10 ft. the water in the reservoir is x ft deep. if the level of the water is increasing at 4 ft/min, how fast is the volume of the water in the reservoir increasing when its depth is 2 ft? NOTE: the volume of a frustrum of a cone of upper base raduis R and lower base raduis r and height h. V = 1/3 pi h (R^2 +r^2 + Rr)
Mathematics
• Stacey Warren - Expert brainly.com
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SOLVED
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