A community for students.
Here's the question you clicked on:
 0 viewing
jarp0120
 one year ago
a reservoir is in the form of a frustrum of a cone with upper base of radius 9 ft and lower base of radius 4ft and altitute of 10 ft. the water in the reservoir is x ft deep. if the level of the water is increasing at 4 ft/min, how fast is the volume of the water in the reservoir increasing when its depth is 2 ft?
NOTE: the volume of a frustrum of a cone of upper base raduis R and lower base raduis r and height h. V = 1/3 pi h (R^2 +r^2 + Rr)
jarp0120
 one year ago
a reservoir is in the form of a frustrum of a cone with upper base of radius 9 ft and lower base of radius 4ft and altitute of 10 ft. the water in the reservoir is x ft deep. if the level of the water is increasing at 4 ft/min, how fast is the volume of the water in the reservoir increasing when its depth is 2 ft? NOTE: the volume of a frustrum of a cone of upper base raduis R and lower base raduis r and height h. V = 1/3 pi h (R^2 +r^2 + Rr)

This Question is Closed

Jarp0120
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443869570610:dw

baru
 one year ago
Best ResponseYou've already chosen the best response.0calculus prob? did that formula come with the problem or did you just add it?

Jarp0120
 one year ago
Best ResponseYou've already chosen the best response.0came from the problem
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.