A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

jarp0120

  • one year ago

a reservoir is in the form of a frustrum of a cone with upper base of radius 9 ft and lower base of radius 4ft and altitute of 10 ft. the water in the reservoir is x ft deep. if the level of the water is increasing at 4 ft/min, how fast is the volume of the water in the reservoir increasing when its depth is 2 ft? NOTE: the volume of a frustrum of a cone of upper base raduis R and lower base raduis r and height h. V = 1/3 pi h (R^2 +r^2 + Rr)

  • This Question is Closed
  1. Jarp0120
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1443869570610:dw|

  2. baru
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    calculus prob? did that formula come with the problem or did you just add it?

  3. Jarp0120
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    came from the problem

  4. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.