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anonymous
 one year ago
I need help in calculus. Can anyone?
anonymous
 one year ago
I need help in calculus. Can anyone?

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amistre64
 one year ago
Best ResponseYou've already chosen the best response.3posting the question might be prudent

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry for a late reply. Can you help me find the derivative of this y=3/5cot^5 x/3+cot^3 x/33cot x/3 x?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3using derivative rules or the other way?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3is that cot^5 a top or bottom of the fraction?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Using the rules. It's on top.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3are those x/3 arguements of the trig function, or is that trig divided by 3?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3\[y=\frac35\cot^5 (\frac{x}3)+\cot^3 (\frac{x}3)3\cot (\frac{x}3) x\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3if we let u=cot(x/3) \[y=\frac35u^5 +u^3 3u x\] how would you attempt to find the derivative of this?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3what is your power rule?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3good, lets use u' instead of du/dx just simpler to write

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3\[y=\frac35u^5 +u^3 3u x\] \[y'=\frac3u^4u' +3u^2u' u' x'\] x'=dx/dx=1 soo \[y'=u'(\frac3u^4 +3u^2 1) 1\] oh, and what will our u' be since u=cot(x/3)?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3bah, code typo .... 3u^4

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3u' is a chain rule as well ... what is your chain rule?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3no, thats power rule .... chain rule is for composition of function

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3a function within a function, within a function, within a function .... f(g(h(...(k(x))))) the derivative is a multiplier effect: f'g'h'...k'

anonymous
 one year ago
Best ResponseYou've already chosen the best response.03/5cot^5(x/3) will be like this 3/5 (5)cot^4(x/9)(csc^2x)?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3close, but i like to work with a simpler writeup 3/5 u^5 would be 3u^4 u' but since u = cot(x/3), u' = csc^2(x/3) * (x/3)'; or 1/3 csc^2(x/3)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Really going to be a tough one for me.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3let u = cot(x/3); u' = 1/3 csc^2(x/3) \[y'=u'(3u^4 +3u^2 1) 1\] \[y'=\frac13\csc^2(\frac{x}3)~(3\cot^4(\frac{x}3) +3\cot^2(\frac{x}3) 1) 1\] or \[y'=\csc^2(\frac{x}3)~(\cot^4(\frac{x}3) \cot^2(\frac{x}3) +\frac13) ~1\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3its not a difficult process, just messy if you try to keep it all ... xish thru the process

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'll try for it. This is, one part of Differential Calculus that I'm really having a hard time.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3it can be daunting, but its really simpler than algebra :) good luck

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Maybe but I don't really know. Thanks.
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