Janu16
  • Janu16
What is the equation of the quadratic graph with a focus of (5, 6) and a directrix of y = 2?
Mathematics
jamiebookeater
  • jamiebookeater
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Janu16
  • Janu16
AlexandervonHumboldt2
  • AlexandervonHumboldt2
ok so |dw:1443885390273:dw|
AlexandervonHumboldt2
  • AlexandervonHumboldt2
|dw:1443885459543:dw|

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Janu16
  • Janu16
yeaa
AlexandervonHumboldt2
  • AlexandervonHumboldt2
(6-2)/2=4/2=2 => 2+2=4 => vertex is (5,4) b will be the distance between the vertex and the directrix or focus. |dw:1443885604489:dw| (x−h)^2=4b(y−k) ((h,k) is vertex ) b=2 (h,k)=(5,4) Plug and get this equation: (x−5)^2=8(y−4) now simplify this equation and find your answer
AlexandervonHumboldt2
  • AlexandervonHumboldt2
simplifying is easy
Janu16
  • Janu16
−one eighth (x − 5)2 + 4?
Janu16
  • Janu16
wait one eighth (x − 5)2 + 4
AlexandervonHumboldt2
  • AlexandervonHumboldt2
yeah 1/8*(x-5)^2+4=y
Janu16
  • Janu16
okk thx!
AlexandervonHumboldt2
  • AlexandervonHumboldt2
np

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