The following graph of f(x)=x^2 has been shifted into the form f(x)=(x-h)^2+k

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The following graph of f(x)=x^2 has been shifted into the form f(x)=(x-h)^2+k

Mathematics
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in that equation (h,k) is the vertex point
ya so im lookinf for k

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y-coordinate of the vertex would be the k |dw:1443886284134:dw| so look at the graph find what's x and y
2?
it should be (x,y) pair
2,2? not sure
you can draw a vertical line like this |dw:1443886489382:dw| when x = 2 y =-1 so (2,-1)
ohhyaa
so what would be the vertex in the given graph ?
2?
wait
-1?
that was an example.
ohh so the vertex is -2? cause that dot is on negative line
\[\huge\rm f(x)=a(x-h)^2+k\] vertex form of parabola where (h,k) is the vertex point shape of the parabola depends on the sign of leading coefficient if a is positive then it will opens up|dw:1443886757241:dw| and when a is negative parabola opens down
|dw:1443886878265:dw| that's the vertex
oookk
or in other words h = horizontal shift k= vertical shift to find k you should know how many units the graph going up or down from the origin
is*
why cant i see the drawing
so if you know that you would get the k?
you cant see it if you are on the phone app.
yes. so what's the k ?
i'll give u an exxample |dw:1443887248429:dw|
-2?
thats what i got
|dw:1443887515749:dw| the point is in first quadrant where x and y both are positive
ohh so positive 2
yes x =2 but we also need y -coordinate so when x = 2 y = what ?
3
right (h,k)= (2,3)
so h is 2 aznd k is 3?
thx so much nnesha!!
np :=) and yes right k=3

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