vera_ewing
  • vera_ewing
Math question
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
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Michele_Laino
  • Michele_Laino
here your linear system can be rewritten as follows: \[\left( {\begin{array}{*{20}{c}} 3&4 \\ 2&5 \end{array}} \right) \cdot \left( {\begin{array}{*{20}{c}} x \\ y \end{array}} \right) = \left( {\begin{array}{*{20}{c}} { - 2} \\ 6 \end{array}} \right)\]
Michele_Laino
  • Michele_Laino
now, we have to find the inverse matrix of the coefficients matrix: \[\left( {\begin{array}{*{20}{c}} 3&4 \\ 2&5 \end{array}} \right)\]
vera_ewing
  • vera_ewing
Ok and then what?

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Michele_Laino
  • Michele_Laino
such inverse matrix, is: \[\left( {\begin{array}{*{20}{c}} {5/7}&{ - 4/7} \\ { - 2/7}&{3/7} \end{array}} \right)\] please check my computations
vera_ewing
  • vera_ewing
Ok, and then how do we find the product of the solution?
Michele_Laino
  • Michele_Laino
it is simple, since the solution of your system is: \[\left( {\begin{array}{*{20}{c}} {5/7}&{ - 4/7} \\ { - 2/7}&{3/7} \end{array}} \right) \cdot \left( {\begin{array}{*{20}{c}} { - 2} \\ 6 \end{array}} \right) = \left( {\begin{array}{*{20}{c}} x \\ y \end{array}} \right)\]
vera_ewing
  • vera_ewing
Ohh so the answer is C?
Michele_Laino
  • Michele_Laino
are you sure?
vera_ewing
  • vera_ewing
I think so...can you check?
Michele_Laino
  • Michele_Laino
the solution of your system, can be rewritten as follows: \[\frac{1}{7}\left( {\begin{array}{*{20}{c}} 5&{ - 4} \\ { - 2}&3 \end{array}} \right) \cdot \left( {\begin{array}{*{20}{c}} { - 2} \\ 6 \end{array}} \right) = \left( {\begin{array}{*{20}{c}} x \\ y \end{array}} \right)\]
vera_ewing
  • vera_ewing
Oh so D! Thanks Michele! :)
Michele_Laino
  • Michele_Laino
correct! :)

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