Stanford University's soccer field has an area of 8800 square yards. Its length is 30 yards longer than its width. 1. Write an expression for each dimension (length and width) of the soccer field. 2.Write an equation and solve for the dimensions of the soccer field.

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Stanford University's soccer field has an area of 8800 square yards. Its length is 30 yards longer than its width. 1. Write an expression for each dimension (length and width) of the soccer field. 2.Write an equation and solve for the dimensions of the soccer field.

Mathematics
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let length = L and width = W, with me so far?
yes
"length is 30 yards longer than its width. " means that L = 30 + W so length = 30 + W and width = W, that takes care of #1

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Other answers:

for #2, we let length*width = area so W(W+30) = 8800 solve for W
Do I distribute the W ?
yes
W^2+30W=8800
good, now subtract 8800 from each side
Is it -8800W^2-8770W?
nope
remember that you cannot combine numbers and variables
W^2+30W-8800=0
So it'll be W^2+30W-8800
yes, now factor
W^2+30W-8800 = ?
can and 10 and 880 work?
nope, think carefully our two factors must add to 30 and multiply to get 8800
W^2+30W-8800 = (W+110)(W-80), know where to go from here?
Do i solve for W?
yes
W=-110 and W=80
good, now remember that W is width, and width must be positive so W = 80
now find L
L=110
good! that should b everything
Thank you so much!!

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