anonymous
  • anonymous
NiCl3 is a strong electrolyte. Determine the concentration of each of the individual ions in a 0.600 M NiCl3 solution.
Chemistry
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SOLVED
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jamiebookeater
  • jamiebookeater
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Rushwr
  • Rushwr
What's ur answer ! I'l just check it !!!
anonymous
  • anonymous
Well my question is on how to get it. How do the charges of the individual ions affect the concentration?
anonymous
  • anonymous
I don't know how to find the concentration of the ions themselves

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Rushwr
  • Rushwr
is that all the data given ?/
anonymous
  • anonymous
Yes and that Na is a +3 charge and Cl is -1
Rushwr
  • Rushwr
Okai I'm not soo sure with this though but I'll try. First we will write the dissociation equation for this \[NiCl _{3} \rightarrow Ni ^{3+} + 3Cl ^{-}\]
anonymous
  • anonymous
okay
Rushwr
  • Rushwr
So I'm just sayn try using the values I'm giving. Ni^3+ = 0.6M Cl^- = 1.8M
Rushwr
  • Rushwr
Did u check ?
anonymous
  • anonymous
Yes! It's right! How did you get those values though?
Rushwr
  • Rushwr
look at the dissociation equation. The moles of NiCl3 is equal to the moles of Ni^3+ right? If we consider the same volume the concentration becomes equal. And we can see the moles of Cl^-1 is thrice as of Ni^3+ so u multiply 0.6 by 3 = 1.8M
Rushwr
  • Rushwr
I'm sorry I didn't see that comment coming !

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