## anonymous one year ago NiCl3 is a strong electrolyte. Determine the concentration of each of the individual ions in a 0.600 M NiCl3 solution.

1. Rushwr

What's ur answer ! I'l just check it !!!

2. anonymous

Well my question is on how to get it. How do the charges of the individual ions affect the concentration?

3. anonymous

I don't know how to find the concentration of the ions themselves

4. Rushwr

is that all the data given ?/

5. anonymous

Yes and that Na is a +3 charge and Cl is -1

6. Rushwr

Okai I'm not soo sure with this though but I'll try. First we will write the dissociation equation for this $NiCl _{3} \rightarrow Ni ^{3+} + 3Cl ^{-}$

7. anonymous

okay

8. Rushwr

So I'm just sayn try using the values I'm giving. Ni^3+ = 0.6M Cl^- = 1.8M

9. Rushwr

Did u check ?

10. anonymous

Yes! It's right! How did you get those values though?

11. Rushwr

look at the dissociation equation. The moles of NiCl3 is equal to the moles of Ni^3+ right? If we consider the same volume the concentration becomes equal. And we can see the moles of Cl^-1 is thrice as of Ni^3+ so u multiply 0.6 by 3 = 1.8M

12. Rushwr

I'm sorry I didn't see that comment coming !