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anonymous

  • one year ago

DNA molecules consist of chemically linked sequences of the bases adenine, quinine, cytosine, and thymine, denoted A, G, C, and T. A sequence of 3 bases is called a codon. A base may appear more than once in a codon. The bases A and G are purines, while C and T are pyrimidines. How many codons are there whose first base is a purine and the second and third bases are pyrimidines? I know the answer is 8, but why is it 8? Why is it 2^3?

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  1. triciaal
    • one year ago
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    you might get a better response if you post in Biology. if this is an application probability then|dw:1443893477530:dw|

  2. amistre64
    • one year ago
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    there are 2 sets that we can divide this into to start with; those that start with A, and those that start with G each set can be divided into subsets; those that follow with a C, and those that follow with a T; so we are up to 2 sets, that have 2 elements each. 4 in total these 4 elements, can either end with a C or a T, so each one can be finished in 2 ways ... 4*2 = 8

  3. amistre64
    • one year ago
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    |dw:1443897549490:dw|

  4. triciaal
    • one year ago
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    independent events. 3 times. each 2/4 = 1/2

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