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anonymous

  • one year ago

Find the area of a sector with an arc length of 60in. And a radius of 15in

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  1. kawii2004
    • one year ago
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    add 60 and 15 if you dont see the awnser multiply of subtract

  2. anonymous
    • one year ago
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    Sorry what do you mean? The answers are: A. 117.75 inches squared B. 282.60 inches squared C. 450 inches squared D. 6,750 inches squared

  3. kawii2004
    • one year ago
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    add

  4. triciaal
    • one year ago
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    |dw:1443905817129:dw|

  5. triciaal
    • one year ago
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    |dw:1443905951262:dw|

  6. triciaal
    • one year ago
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    |dw:1443906055728:dw|

  7. anonymous
    • one year ago
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    Lol I'm so confused

  8. triciaal
    • one year ago
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    the area of the sector is the same ratio as the length of the arc to the circumference.

  9. mathmate
    • one year ago
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    Let's not confuse arc-length with angles. 60" is the arc-length, and 15 is the radius. If you have learned radians, you will find the angle subtended is \(\theta\) = arc-length / radius = 60/15=4 radians. Area of a sector = \((1/2)\theta r^2= (1/2)*4~ radians *15^2~ in.^2\) \(=450~ in.^2\) If you have not learned radians, use @triciaal 's formula: area of sector / area of circle = arc length of sector / circumference of circle So area of sector = area of circle * arc length of sector / circumference of circle = \(\pi r^2 * (60/(2\pi (r)) in^2\) = \(2r^2\) = \(450~in^2\)

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