A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Find the area of a sector with an arc length of 60in. And a radius of 15in
anonymous
 one year ago
Find the area of a sector with an arc length of 60in. And a radius of 15in

This Question is Open

kawii2004
 one year ago
Best ResponseYou've already chosen the best response.0add 60 and 15 if you dont see the awnser multiply of subtract

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry what do you mean? The answers are: A. 117.75 inches squared B. 282.60 inches squared C. 450 inches squared D. 6,750 inches squared

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443905817129:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443905951262:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443906055728:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0the area of the sector is the same ratio as the length of the arc to the circumference.

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1Let's not confuse arclength with angles. 60" is the arclength, and 15 is the radius. If you have learned radians, you will find the angle subtended is \(\theta\) = arclength / radius = 60/15=4 radians. Area of a sector = \((1/2)\theta r^2= (1/2)*4~ radians *15^2~ in.^2\) \(=450~ in.^2\) If you have not learned radians, use @triciaal 's formula: area of sector / area of circle = arc length of sector / circumference of circle So area of sector = area of circle * arc length of sector / circumference of circle = \(\pi r^2 * (60/(2\pi (r)) in^2\) = \(2r^2\) = \(450~in^2\)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.