Two towns on the map are 4 1/2 inches apart. What is the actual distance in miles between the two towns? Explain how you determined your answer.

- anonymous

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- anonymous

@hartnn

- anonymous

I know that for this, I may have to find the domain and range, right?

- anonymous

@hartnn please? I could use your help...

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- anonymous

@dan815

- triciaal

|dw:1443909705309:dw|

- anonymous

What? I don't get it... I apologize @triciaal

- triciaal

you need to know the scale factor.
how many miles on the ground in real life is represented by one inch on paper.

- anonymous

Ok but how can I find the actual distance between the two towns?

- anonymous

This is on a "functions" homework packet

- triciaal

example the mall is 3 miles from your house and the school is 1/2 mile from your house how would you show that on a map?

- anonymous

I honestly don't know

- triciaal

|dw:1443911214002:dw|

- anonymous

So how can I use this to find the actual distance in miles between the two towns?

- anonymous

I just stink when it comes to this kind of math

- triciaal

scale 2 cm represents 1 mile so 1/2 mile = 1 cm therefore I put the school 1 cm from your house same process put the mall 6 cm from your house

- anonymous

Would it be 4 1/2 miles? Because I don't think that would be correct

- anonymous

For my original equation

- triciaal

for this problem you have the distance on the map and you need the distance on the ground

- anonymous

I don't think I do. i think it's just asking for the distance between the two towns. And it only gives me the 4 1/2 inches apart thing. How can I figure out the distance "in miles" using such little information...?

- triciaal

use the scale factor
how many miles on the ground is represented by one inch on the paper? lets say "m" then the distance on the ground would be 4 1/2 * m

- anonymous

But what would "m" be? What does is represent?

- anonymous

This is a problem that somehow has to do with functions. For Algebra 2

- triciaal

the number of miles on the ground for 1 inch on paper

- anonymous

There is no paper related in the problem. And you keep saying this whole thing about the paper

- triciaal

|dw:1443911734901:dw|

- anonymous

I don't know... I guess I'll figure it out on my own then... Thanks for the help

- triciaal

the map is the paper

- anonymous

Because I don't think your answer is correct

- anonymous

I just don't understand why that would be the miles

- anonymous

They wouldn't just give you the answer

- anonymous

And I know that you'd have to do more work to find miles from inches, than to simply say that it would be 4 1/2 miles, just because that is the inches

- triciaal

read again that is not what I have !

- anonymous

Yes you do!

- triciaal

i said 4 1/2 times the scale factor

- anonymous

I can't just put 4 1/2(m)

- anonymous

It needs an actual distance

- triciaal

m is the scale factor one inch = how many miles?

- anonymous

I don't know 1/2?

- triciaal

do you have the original problem? read slower did they tell you the scale factor? Is this related to another question where the factor was given?

- anonymous

No... This is the entire question. Two towns are 4 1/2 inches apart. What is the actual distance in miles between the two towns? Explain how you determined your answer

- triciaal

do you understand the example I used with a scale factor of 2 cm to 1 mile to show the mall 6 cm from your house 3 miles?

- anonymous

No I don't... I'll just figure it out on my own. Thanks for the help

- triciaal

|dw:1443912336140:dw|

- triciaal

distance town A to town B = 4 1/2 *m where m is the distance represented by one inch. cannot give a number if not given a number for m. leave it as a function.

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