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unimatix
 one year ago
Simplify Algebra (in comments)
unimatix
 one year ago
Simplify Algebra (in comments)

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unimatix
 one year ago
Best ResponseYou've already chosen the best response.1\[4(8)(28x)^3(x^29)^3+3(2x)(28x)^4(x^29)^2\]

unimatix
 one year ago
Best ResponseYou've already chosen the best response.1The next step shown looks like \[4(28x)^3(x^29)^2(20x^23x72)\]

unimatix
 one year ago
Best ResponseYou've already chosen the best response.1I'm having trouble understand how that was arrived at.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hold on solving them

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright here it is, use this website to do the rest http://prntscr.com/8nfl0b

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2take out the common factor

unimatix
 one year ago
Best ResponseYou've already chosen the best response.1I just need it simplified to the second step.

unimatix
 one year ago
Best ResponseYou've already chosen the best response.1because then I am solving equal to 0.

unimatix
 one year ago
Best ResponseYou've already chosen the best response.1that's where my confusion is

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[4(8)\color{Red}{(28x)^3}\color{blue}{(x^29)^3}+3(2x)\color{Red}{(28x)^4}\color{blue}{(x^29)^2}\] see there is GCF (greatest common factor

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2dw:1443912816495:dw now what is common in both terms sorry about the writing ....:/\:

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\(\color{blue}{\text{Originally Posted by}}\) @unimatix The next step shown looks like \[4(28x)^3(x^29)^2(20x^23x72)\] \(\color{blue}{\text{End of Quote}}\) i think you forgot the negative sign it's `4`

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[4(8)\color{Red}{(28x)^3}\color{blue}{(x^29)^3}+3(2x)\color{Red}{(28x)^4}\color{blue}{(x^29)^2}\] (x^29)^3 can be wriitten as (x^29)^2(x^29) \[4(8)\color{Red}{(28x)^3}\color{blue}{(x^29)^2(x^29)}+3(2x)\color{Red}{(28x)^4}\color{blue}{(x^29)^2}\] so as you can (x^29)^2 is common

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2ohhh well you're not online can't work without u

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1\(4(8)(28x)^3(x^29)^3+3(2x)(28x)^4(x^29)^2\) \(=32(28x)^3(x^29)^3+3(2x)(28x)^4(x^29)^2\) \(=(2  8x)^3(x^2  9)^2[32(x^29)+3(2x)(28x)]\) \(=(2  8x)^3(x^2  9)^2[32x^2+288+12x  48x^2]\) \(=(2  8x)^3(x^2  9)^2(80x^2+12x + 288)\)

unimatix
 one year ago
Best ResponseYou've already chosen the best response.13rd line down I'm confused

unimatix
 one year ago
Best ResponseYou've already chosen the best response.1How are you moving the 32?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1\(=(2  8x)^3(x^2  9)^2(80x^2+12x + 288)\) \(= 4 (2  8x)^3(x^2  9)^2(20x^2 3 x  72)\)

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Here is the second line. You're ok with it? \(=32(28x)^3(x^29)^3+3(2x)(28x)^4(x^29)^2\)

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1From the 2nd line to the third line, we factor out two factors: \(=32\color{red}{(28x)^3}\color{purple}{(x^29)^3}+3(2x)\color{red}{(28x)^4}\color{purple}{(x^29)^2}\)

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1We have (in red) the factor 2  8x. It is to the 3 power in the first part, and to the 4th power in the second part. We can factor out (8  2x)^3. Then (in purple) we have the factor x^2  9 to the 3rd power and to the 2th power. We can factor out (x^2  9)^2. Ok so far?

unimatix
 one year ago
Best ResponseYou've already chosen the best response.1OKay I understand that step

unimatix
 one year ago
Best ResponseYou've already chosen the best response.1good on the 4th line too

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Here is the 3rd line after factoring out those two factors: \(=\color{red}{(2  8x)^3}\color{purple}{(x^2  9)^2}[32\color{purple}{(x^29)}+3(2x)\color{red}{(28x)}]\)

unimatix
 one year ago
Best ResponseYou've already chosen the best response.1I'm not really used to factoring out those factors I guess.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Then the 5th line is just simplification inside the square brackets.

unimatix
 one year ago
Best ResponseYou've already chosen the best response.1That all makes sense. It's pretty straightforward. Thank you!

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Finally the last line which is on the next response above, is simply taking out a factor of 4 from inside the parentheses and bringing it out.
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