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Babynini
 one year ago
Limits!
Babynini
 one year ago
Limits!

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Babynini
 one year ago
Best ResponseYou've already chosen the best response.0So direct substitution didn't work. Then I tried ((t4)^4)/((t4)^3) Does that work? where would I go from there?

unimatix
 one year ago
Best ResponseYou've already chosen the best response.1You want to plug in values increasing close to 4 for t.

unimatix
 one year ago
Best ResponseYou've already chosen the best response.1like 3.9, 4.1 then 3.99, 4.01 etc... until you see the pattern and there is your answer

unimatix
 one year ago
Best ResponseYou've already chosen the best response.1yes number approaching 4

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0Ok, let me put it into my calc, just a second :)

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0does 5.33 look right?

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0hrm, it's saying that's wrong.

unimatix
 one year ago
Best ResponseYou've already chosen the best response.15.333(repeating) is right believe.

unimatix
 one year ago
Best ResponseYou've already chosen the best response.1Maybe try imputing 16/3

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0Oh yay! It accepted 16/3 Thanks so much :)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1t^4  256 = (t^2)^2  (16)^2 t^4  256 = (t^2  16)(t^2 + 16) t^4  256 = (t  4)(t+4)(t^2 + 16) t^3  64 = t^3  4^3 t^3  64 = (t4)(t^2 + 4t + 16) ... difference of cubes rule So, \[\Large \frac{t^4256}{t^364} = \frac{(t  4)(t+4)(t^2 + 16)}{(t4)(t^2 + 4t + 16)}\] \[\Large \frac{t^4256}{t^364} = \frac{\cancel{(t  4)}(t+4)(t^2 + 16)}{\cancel{(t4)}(t^2 + 4t + 16)}\] \[\Large \frac{t^4256}{t^364} = \frac{(t+4)(t^2 + 16)}{t^2 + 4t + 16}\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1after that, you can plug in t = 4 because there are no division by zero errors any more (the t4 term in the denominator is gone)

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0ahh that makes sense!! Thanks so much. Yeah, I was trying to figure out how to do it algebraically.
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