## Ac3 one year ago In the figure below, a tin of antioxidants (m1 = 1.3 kg) on a frictionless inclined surface is connected to a tin of corned beef (m2 = 2.3 kg). The pulley is massless and frictionless. An upward force of magnitude F = 5.9 N acts on the corned beef tin, which has a downward acceleration of 5.4 m/s2. What are the tension in the connecting cord and angle β?

1. Ac3

2. Ac3

Irishboy any idea?

3. IrishBoy123

of course have you drawn any free body diagrams? do you have your own thoughts on this?

4. Ac3

yes

5. Ac3

|dw:1443919104377:dw|

6. Ac3

Finding the tension like this gives 4.22. However that's wrong and the reason I know it's wrong is because another one with very similar numbers has the Tension as 2.6

7. Ac3

oh nvm it's right lol

8. Ac3

Now how do I find the angle?

9. IrishBoy123

|dw:1443919249971:dw|

10. Ac3

|dw:1443919309239:dw|

11. Ac3

n is the normal force from the surface on the can

12. Ac3

any ideas on the angle?

13. anonymous

Explain to me how you find tension earlier?

14. anonymous

Because you need that for angle.

15. Ac3

|dw:1443919872349:dw|

16. IrishBoy123

T = 4.243N is good you need $$\beta$$, right?

17. Ac3

yea irishboy

18. Ac3

tension is found through that equation

19. IrishBoy123

obviously so you have for the upper block $$T + mg \sin \beta = ma$$ ?? do you see that

20. Ac3

no not exactly

21. Ac3

is that all in the y?

22. IrishBoy123

|dw:1443920229507:dw|

23. IrishBoy123

|dw:1443920344245:dw|

24. Ac3

OHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH

25. Ac3

that makes sense

26. Ac3

wow i can't believe I couldn't figure that out

27. Ac3

I even drew that exact picture out as well

28. Ac3

thanks Irishboy saving me again

29. anonymous

You mean for the upper block? $mgsin \beta-T=ma$

30. IrishBoy123

@Ac3 blows me away too, every time. good luck!

31. Ac3

no it is indeed +T not -T, that's because they're both going down @Shalante

32. anonymous

m2 is heavier.

33. anonymous

If its going down, then it would start with mg is first. But you got the answer right?

34. Ac3

@IrishBoy123 I use M1 for the mass correct?

35. Ac3

no not yet

36. anonymous

You need to derive a lot.

37. Ac3

I got the angle wrong. Must have messed up the calculation. I got 28 for the positive angle and -61.9 for the negative angle

38. IrishBoy123

@Ac3 run with @Shalante see where you get to. tag me tomorrow otherwise, gtg. good luck!

39. Ac3

what did you get for the angle @Shalante

40. anonymous

Tell me how you got tension first

41. Ac3

T+F-mg=ma(y)

42. Ac3

plug in all values and solve for T. That's how you get tension.

43. Ac3

I got the angle guys

44. Ac3

I guess plugging in all the values at once in the calculator gives you the right answer. lol

45. Ac3

Thanks a lot @IrishBoy123.

46. anonymous

Let me guess the angle.

47. anonymous

Nvm. Someone tagged me.