In the figure below, a tin of antioxidants (m1 = 1.3 kg) on a frictionless inclined surface is connected to a tin of corned beef (m2 = 2.3 kg). The pulley is massless and frictionless. An upward force of magnitude F = 5.9 N acts on the corned beef tin, which has a downward acceleration of 5.4 m/s2. What are the tension in the connecting cord and angle β?

- Ac3

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- Ac3

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- Ac3

Irishboy any idea?

- IrishBoy123

of course
have you drawn any free body diagrams? do you have your own thoughts on this?

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## More answers

- Ac3

yes

- Ac3

|dw:1443919104377:dw|

- Ac3

Finding the tension like this gives 4.22. However that's wrong and the reason I know it's wrong is because another one with very similar numbers has the Tension as 2.6

- Ac3

oh nvm it's right lol

- Ac3

Now how do I find the angle?

- IrishBoy123

|dw:1443919249971:dw|

- Ac3

|dw:1443919309239:dw|

- Ac3

n is the normal force from the surface on the can

- Ac3

any ideas on the angle?

- anonymous

Explain to me how you find tension earlier?

- anonymous

Because you need that for angle.

- Ac3

|dw:1443919872349:dw|

- IrishBoy123

T = 4.243N is good
you need \(\beta\), right?

- Ac3

yea irishboy

- Ac3

tension is found through that equation

- IrishBoy123

obviously
so you have for the upper block \(T + mg \sin \beta = ma \) ?? do you see that

- Ac3

no not exactly

- Ac3

is that all in the y?

- IrishBoy123

|dw:1443920229507:dw|

- IrishBoy123

|dw:1443920344245:dw|

- Ac3

OHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH

- Ac3

that makes sense

- Ac3

wow i can't believe I couldn't figure that out

- Ac3

I even drew that exact picture out as well

- Ac3

thanks Irishboy saving me again

- anonymous

You mean for the upper block?
\[mgsin \beta-T=ma\]

- IrishBoy123

@Ac3
blows me away too, every time. good luck!

- Ac3

no it is indeed +T not -T, that's because they're both going down @Shalante

- anonymous

m2 is heavier.

- anonymous

If its going down, then it would start with mg is first.
But you got the answer right?

- Ac3

@IrishBoy123 I use M1 for the mass correct?

- Ac3

no not yet

- anonymous

You need to derive a lot.

- Ac3

I got the angle wrong. Must have messed up the calculation. I got 28 for the positive angle and -61.9 for the negative angle

- IrishBoy123

@Ac3 run with @Shalante
see where you get to.
tag me tomorrow otherwise, gtg. good luck!

- Ac3

what did you get for the angle @Shalante

- anonymous

Tell me how you got tension first

- Ac3

T+F-mg=ma(y)

- Ac3

plug in all values and solve for T. That's how you get tension.

- Ac3

I got the angle guys

- Ac3

I guess plugging in all the values at once in the calculator gives you the right answer. lol

- Ac3

Thanks a lot @IrishBoy123.

- anonymous

Let me guess the angle.

- anonymous

Nvm.
Someone tagged me.

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