Ac3
  • Ac3
In the figure below, a tin of antioxidants (m1 = 1.3 kg) on a frictionless inclined surface is connected to a tin of corned beef (m2 = 2.3 kg). The pulley is massless and frictionless. An upward force of magnitude F = 5.9 N acts on the corned beef tin, which has a downward acceleration of 5.4 m/s2. What are the tension in the connecting cord and angle β?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Ac3
  • Ac3
1 Attachment
Ac3
  • Ac3
Irishboy any idea?
IrishBoy123
  • IrishBoy123
of course have you drawn any free body diagrams? do you have your own thoughts on this?

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More answers

Ac3
  • Ac3
yes
Ac3
  • Ac3
|dw:1443919104377:dw|
Ac3
  • Ac3
Finding the tension like this gives 4.22. However that's wrong and the reason I know it's wrong is because another one with very similar numbers has the Tension as 2.6
Ac3
  • Ac3
oh nvm it's right lol
Ac3
  • Ac3
Now how do I find the angle?
IrishBoy123
  • IrishBoy123
|dw:1443919249971:dw|
Ac3
  • Ac3
|dw:1443919309239:dw|
Ac3
  • Ac3
n is the normal force from the surface on the can
Ac3
  • Ac3
any ideas on the angle?
anonymous
  • anonymous
Explain to me how you find tension earlier?
anonymous
  • anonymous
Because you need that for angle.
Ac3
  • Ac3
|dw:1443919872349:dw|
IrishBoy123
  • IrishBoy123
T = 4.243N is good you need \(\beta\), right?
Ac3
  • Ac3
yea irishboy
Ac3
  • Ac3
tension is found through that equation
IrishBoy123
  • IrishBoy123
obviously so you have for the upper block \(T + mg \sin \beta = ma \) ?? do you see that
Ac3
  • Ac3
no not exactly
Ac3
  • Ac3
is that all in the y?
IrishBoy123
  • IrishBoy123
|dw:1443920229507:dw|
IrishBoy123
  • IrishBoy123
|dw:1443920344245:dw|
Ac3
  • Ac3
OHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH
Ac3
  • Ac3
that makes sense
Ac3
  • Ac3
wow i can't believe I couldn't figure that out
Ac3
  • Ac3
I even drew that exact picture out as well
Ac3
  • Ac3
thanks Irishboy saving me again
anonymous
  • anonymous
You mean for the upper block? \[mgsin \beta-T=ma\]
IrishBoy123
  • IrishBoy123
@Ac3 blows me away too, every time. good luck!
Ac3
  • Ac3
no it is indeed +T not -T, that's because they're both going down @Shalante
anonymous
  • anonymous
m2 is heavier.
anonymous
  • anonymous
If its going down, then it would start with mg is first. But you got the answer right?
Ac3
  • Ac3
@IrishBoy123 I use M1 for the mass correct?
Ac3
  • Ac3
no not yet
anonymous
  • anonymous
You need to derive a lot.
Ac3
  • Ac3
I got the angle wrong. Must have messed up the calculation. I got 28 for the positive angle and -61.9 for the negative angle
IrishBoy123
  • IrishBoy123
@Ac3 run with @Shalante see where you get to. tag me tomorrow otherwise, gtg. good luck!
Ac3
  • Ac3
what did you get for the angle @Shalante
anonymous
  • anonymous
Tell me how you got tension first
Ac3
  • Ac3
T+F-mg=ma(y)
Ac3
  • Ac3
plug in all values and solve for T. That's how you get tension.
Ac3
  • Ac3
I got the angle guys
Ac3
  • Ac3
I guess plugging in all the values at once in the calculator gives you the right answer. lol
Ac3
  • Ac3
Thanks a lot @IrishBoy123.
anonymous
  • anonymous
Let me guess the angle.
anonymous
  • anonymous
Nvm. Someone tagged me.

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