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anonymous

  • one year ago

Given that h(x) = 4x+5 and (h-j)(x) = x-2, find j(x).

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  1. anonymous
    • one year ago
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    @freckles

  2. anonymous
    • one year ago
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    I think I have an idea, but I don't think it is correct

  3. anonymous
    • one year ago
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    Would I do 4(x-2)+5

  4. mathstudent55
    • one year ago
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    h(x) = 4x+5 and (h-j)(x) = x-2, find j(x) (h-j)(x) = h(x) - j(x) x - 2 = 4x + 5 - j(x) Solve for j(x)

  5. anonymous
    • one year ago
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    Ok. Would that be -7/3 ?

  6. mathstudent55
    • one year ago
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    x - 2 = 4x + 5 - j(x) Add j(x) to both sides: j(x) + x - 2 = 4x + 5 Subtract x from both sides & add 2 to both sides: j(x) = 3x + 7

  7. anonymous
    • one year ago
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    Oh ok.. And then once I plug them in together I should get x-2 right?

  8. mathstudent55
    • one year ago
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    Let's check. We must have h(x) - j(x) = x - 2 h(x) = 4x + 5 j(x) = 3x + 7 (h-j)(x) = h(x) - j(x) = 4x + 5 - (3x + 7) = 4x + 5 - 3x - 7 = x - 2

  9. anonymous
    • one year ago
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    Thank you so much! I thought it was something along the likes of that, but I just wanted to double check.

  10. mathstudent55
    • one year ago
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    Yes, but the answer is just j(x) = x - 2 I just plugged it in to check if j(x) = x - 2 was the correct answer.

  11. mathstudent55
    • one year ago
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    You're welcome.

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spraguer (Moderator)
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