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anonymous

  • one year ago

Given that f(x) = 2x+1 and g(x) = 3x-2, what value(s) of x are excluded from the domain of (f/g)(x)? I know how to set it up, but I don't understand the whole "exclusion" of the "domain"

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  1. Vocaloid
    • one year ago
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    |dw:1443919025462:dw| hint: the values excluded from the domain are: the x-values that will make the denominator equal to 0

  2. anonymous
    • one year ago
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    Yeah like when the = sign has a / across it, right? Would I divide 2x by 3x and 1 by 2?

  3. Vocaloid
    • one year ago
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    nope, we can't do that because of these|dw:1443919175086:dw|

  4. Vocaloid
    • one year ago
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    don't change the function

  5. anonymous
    • one year ago
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    Oh right, so how would I do it?

  6. Vocaloid
    • one year ago
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    set the denominator equal to 0 and solve for x

  7. anonymous
    • one year ago
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    so 3x-2=0?

  8. Vocaloid
    • one year ago
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    right, so x = ?

  9. anonymous
    • one year ago
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    which would be 2/3

  10. anonymous
    • one year ago
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    Would I have to do the same thing to the numbers on the top? like 2x+1=0

  11. Vocaloid
    • one year ago
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    nope, just the denominator

  12. Vocaloid
    • one year ago
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    remember: when we divide two numbers, the numerator can be anything, but the denominator cannot be 0

  13. anonymous
    • one year ago
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    Ok, and then I would divide them together? or would I do KCF?

  14. anonymous
    • one year ago
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    Keep it change it flip it

  15. Vocaloid
    • one year ago
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    no, you're done here, you found x = 2/3, that's your answer.

  16. anonymous
    • one year ago
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    Really?

  17. anonymous
    • one year ago
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    Oh wow.. Thank you!

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