anonymous
  • anonymous
Given that f(x) = 2x+1 and g(x) = 3x-2, what value(s) of x are excluded from the domain of (f/g)(x)? I know how to set it up, but I don't understand the whole "exclusion" of the "domain"
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Vocaloid
  • Vocaloid
|dw:1443919025462:dw| hint: the values excluded from the domain are: the x-values that will make the denominator equal to 0
anonymous
  • anonymous
Yeah like when the = sign has a / across it, right? Would I divide 2x by 3x and 1 by 2?
Vocaloid
  • Vocaloid
nope, we can't do that because of these|dw:1443919175086:dw|

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Vocaloid
  • Vocaloid
don't change the function
anonymous
  • anonymous
Oh right, so how would I do it?
Vocaloid
  • Vocaloid
set the denominator equal to 0 and solve for x
anonymous
  • anonymous
so 3x-2=0?
Vocaloid
  • Vocaloid
right, so x = ?
anonymous
  • anonymous
which would be 2/3
anonymous
  • anonymous
Would I have to do the same thing to the numbers on the top? like 2x+1=0
Vocaloid
  • Vocaloid
nope, just the denominator
Vocaloid
  • Vocaloid
remember: when we divide two numbers, the numerator can be anything, but the denominator cannot be 0
anonymous
  • anonymous
Ok, and then I would divide them together? or would I do KCF?
anonymous
  • anonymous
Keep it change it flip it
Vocaloid
  • Vocaloid
no, you're done here, you found x = 2/3, that's your answer.
anonymous
  • anonymous
Really?
anonymous
  • anonymous
Oh wow.. Thank you!

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