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|dw:1443928609926:dw|

yes :)

yes correct :)

\[m=\varrho A\]

you are using integrals, just easy ones that don't need doing

Suppose I want to find the center of mass of below weird shape.
|dw:1443948450651:dw|

make that
\[\sum \delta a_i \delta r_i \sigma_i\]

I think using plumbline is not allowed because it is more of experimental method...

Exactly! expecting this kindof proof... please keep going...

\[\Rightarrow \vec{\rm CM'} = \vec{\rm CM} \]

wot the frog

that looks really nice!

yeah, that's good!

Ahh nice! nice! I sew it now!

o.o

when you see the relationship for the first time, this is really a beautiful result!

We get that\[\rm \vec{CM} = CM( CM_1, CM_2, \cdots, CM_n) \]

I just proved it for \(n=2\) but you can see what's happening here.

Yup, by induction it follows for n parts :)

let me give you a nice question in another thread maybe

I wonder if this works for finding the electric dipole moment as well?

Negative mass system!!