anonymous
  • anonymous
Simplify 1 / (1+a^n) + 1/(1+a^-n)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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freckles
  • freckles
hint: multiply that second fraction by a^n/a^n
anonymous
  • anonymous
Thanks but does it cancel out th denominater for the second fraction
freckles
  • freckles
\[1 \cdot a_n=? \\ (1+a^{-n}) \cdot a_n=1 \cdot a_n +a^{-n} \cdot a^{n} =?\]

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More answers

anonymous
  • anonymous
Wouldn't it be 1+a as the denimontar
freckles
  • freckles
those one n's were suppose to be exponents (not subscipts)
freckles
  • freckles
\[1 \cdot a^n=a^n \\ (1+a^{-n}) \cdot a^n=1 \cdot a^n+a^{-n} a^{n} \text{ by distributive law } \\ \text{ now do you know law of exponents? }\]
freckles
  • freckles
if you have the same base and you are multiplying what do you do with the exponents ?
anonymous
  • anonymous
Add
freckles
  • freckles
\[(1+a^{-n})a^n=a^n+a^{-n+n}=?\]
freckles
  • freckles
-n+n=?
anonymous
  • anonymous
0
freckles
  • freckles
right and a^0=?
anonymous
  • anonymous
One
freckles
  • freckles
\[\frac{1}{1+a^{n}}+\frac{a^n}{1+a^{n}}=?\]
freckles
  • freckles
you see you have the same denominator
freckles
  • freckles
now you can write as one fraction
freckles
  • freckles
\[\frac{1+a^{n}}{1+a^{n}}=?\]
anonymous
  • anonymous
1
freckles
  • freckles
right and this is of coursing assuming a>0
freckles
  • freckles
a could be less than 0 depending on n we could say a lot about the domain restrictions lol
freckles
  • freckles
but I'm sure they are just looking for 1
anonymous
  • anonymous
Ok tysm
freckles
  • freckles
np

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