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anonymous
 one year ago
Simplify
1 / (1+a^n) + 1/(1+a^n)
anonymous
 one year ago
Simplify 1 / (1+a^n) + 1/(1+a^n)

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freckles
 one year ago
Best ResponseYou've already chosen the best response.1hint: multiply that second fraction by a^n/a^n

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks but does it cancel out th denominater for the second fraction

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[1 \cdot a_n=? \\ (1+a^{n}) \cdot a_n=1 \cdot a_n +a^{n} \cdot a^{n} =?\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wouldn't it be 1+a as the denimontar

freckles
 one year ago
Best ResponseYou've already chosen the best response.1those one n's were suppose to be exponents (not subscipts)

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[1 \cdot a^n=a^n \\ (1+a^{n}) \cdot a^n=1 \cdot a^n+a^{n} a^{n} \text{ by distributive law } \\ \text{ now do you know law of exponents? }\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1if you have the same base and you are multiplying what do you do with the exponents ?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[(1+a^{n})a^n=a^n+a^{n+n}=?\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{1}{1+a^{n}}+\frac{a^n}{1+a^{n}}=?\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1you see you have the same denominator

freckles
 one year ago
Best ResponseYou've already chosen the best response.1now you can write as one fraction

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{1+a^{n}}{1+a^{n}}=?\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1right and this is of coursing assuming a>0

freckles
 one year ago
Best ResponseYou've already chosen the best response.1a could be less than 0 depending on n we could say a lot about the domain restrictions lol

freckles
 one year ago
Best ResponseYou've already chosen the best response.1but I'm sure they are just looking for 1
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