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anonymous

  • one year ago

plz help i really need i will fan and medal. An ant has a length of approximately 7 × 10^ -3 meters and an anaconda has a length of approximately 6 x 10^0 meters. About how many times longer is the anaconda as compared to the ant?

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  1. unimatix
    • one year ago
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    Anything to the zero power is 1. So 6 x 10^0 is just 6 * 1.

  2. anonymous
    • one year ago
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    so what the comparsion

  3. unimatix
    • one year ago
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    Then when you have 10^-3 you just move the decimal place to the left 3 times.

  4. anonymous
    • one year ago
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    im still confused

  5. unimatix
    • one year ago
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    |dw:1443930737970:dw|

  6. unimatix
    • one year ago
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    |dw:1443930810767:dw|

  7. freckles
    • one year ago
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    About how many times longer is the anaconda as compared to the ant? since we see times think about dividing anaconda's length by the ant's length

  8. anonymous
    • one year ago
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    so how would if figure out the comparison

  9. freckles
    • one year ago
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    I put anaconda on top because we want to know how many times longer the anaconda is compared to the other guy

  10. anonymous
    • one year ago
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    do i only divide the first numbers

  11. freckles
    • one year ago
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    there are two numbers the anaconda's length which is given by 6*10^0 and the ant's length which is given by 7*10^(-3) you divide anaconda's length by ant's length

  12. freckles
    • one year ago
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    \[\frac{6 \cdot 10^{0}}{7 \cdot 10^{-3}}\]

  13. freckles
    • one year ago
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    you could write as two separate fractions if you want though

  14. freckles
    • one year ago
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    \[\frac{6}{7} \cdot \frac{10^0}{10^{-3}}\]

  15. freckles
    • one year ago
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    use law of exponents on the second fraction

  16. freckles
    • one year ago
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    do 6/7 for the first fraction

  17. anonymous
    • one year ago
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    1.166

  18. freckles
    • one year ago
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    you did 6/7?

  19. anonymous
    • one year ago
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    yes did i not do it right :(

  20. freckles
    • one year ago
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    actually you did 7/6 instead of 6/7

  21. anonymous
    • one year ago
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    o ok then it o.875

  22. anonymous
    • one year ago
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    sorry 0.857

  23. freckles
    • one year ago
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    yep that is approximately correct \[\frac{6 \cdot 10^{0}}{7 \cdot 10^{-3}} \\ =\frac{6}{7} \cdot \frac{10^{0}}{10^{-3}} \\ =.857 \cdot 10^{0-(-3)}\] once you simplify that one exponent we have one more step

  24. anonymous
    • one year ago
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    how do i simplify the exponent

  25. freckles
    • one year ago
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    well 0-(-3) is the same 0+3... wait what is the goal put answer in scientific notation or decimal notation ?

  26. anonymous
    • one year ago
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    to find the comparison of the ant and the anaconda

  27. freckles
    • one year ago
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    so I guess it doesn't matter what form?

  28. anonymous
    • one year ago
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    put it in scientific form

  29. freckles
    • one year ago
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    anyways let's aim for scientific notation since there other numbers were in scientific notation but honestly have no clue what notation they want the answer in

  30. freckles
    • one year ago
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    \[\frac{6 \cdot 10^{0}}{7 \cdot 10^{-3}} \\ =\frac{6}{7} \cdot \frac{10^{0}}{10^{-3}} \\ =.857 \cdot 10^{0-(-3)}\] so you should see 0-(-3) is 3

  31. freckles
    • one year ago
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    \[=.857 \cdot 10^{3}\]

  32. freckles
    • one year ago
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    now this is not in scientific notation yet

  33. freckles
    • one year ago
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    we need the decimal in the first number to be between the 8 and 5

  34. anonymous
    • one year ago
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    so its .857. 10 to the power of tree

  35. freckles
    • one year ago
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    tree :p

  36. anonymous
    • one year ago
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    sorry three

  37. freckles
    • one year ago
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    and no for it to be scientific notation we want one digit to the left of the decimal point for the first number that digit can be 1,2,3,4,5,6,7,8, or 9 (or a negative version of those numbers)

  38. anonymous
    • one year ago
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    can u help me with another one

  39. freckles
    • one year ago
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    \[.857 \cdot 10^{3} =8.57 \cdot 10^?\]

  40. freckles
    • one year ago
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    can you guess what the ? is

  41. anonymous
    • one year ago
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    -3

  42. freckles
    • one year ago
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    we we only moved the decimal once and we moved the decimal left so moving it once you will either have 3+1 or 3-1 the direction you move it in determines if it was the adding 1 or the subtract 1

  43. anonymous
    • one year ago
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    o ok so i would be 2

  44. freckles
    • one year ago
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    \[.857 \cdot 10^{3} =8.75 \cdot 10^{-1} \cdot 10^{3} =8.57 \cdot 10^{3+(-1)} \\ =8.57 \cdot 10^{2}\] that is right and this answer is in scientific notation

  45. anonymous
    • one year ago
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    by the way do u mind helping me with another one

  46. freckles
    • one year ago
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    sure

  47. anonymous
    • one year ago
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    The total number of living humans on Earth was converted to scientific notation using an online calculator and was reported to be approximately 7.158 × 109. Write Earth's population as a single digit times an integer power of 10 and in standard form.

  48. anonymous
    • one year ago
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    7.158 * 10^9

  49. freckles
    • one year ago
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    so it is looking for us to round 7.158 it seems

  50. freckles
    • one year ago
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    to the nearest integer

  51. freckles
    • one year ago
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    then tack on the 10^9 part

  52. freckles
    • one year ago
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    but then it also looks like it is asking another question

  53. freckles
    • one year ago
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    to write the number in standard form afterwards

  54. freckles
    • one year ago
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    so first step round 7.158 to the nearest integer

  55. anonymous
    • one year ago
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    soo 7.000 times 10^9 the rewrite in standard form

  56. freckles
    • one year ago
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    right you don't need all of those zeros though

  57. freckles
    • one year ago
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    \[7 \times 10^{9}\]

  58. anonymous
    • one year ago
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    ok so just 7. or just 7

  59. freckles
    • one year ago
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    you can write any one of the following: 7.000000000000000000000 7.00000000000000 7.000000000 7.0000 7.00 7.0 7. 7 all of these are fine all of these say 7 I prefer just 7 (also I could have continued with this list :p)

  60. anonymous
    • one year ago
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    ya i think 7 is easy

  61. freckles
    • one year ago
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    now what we are gonna do is right 7 then a bunch of zeros ... |dw:1443932279973:dw|

  62. anonymous
    • one year ago
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    how would we write \[7\times 19^{9}\]

  63. freckles
    • one year ago
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    |dw:1443932358026:dw|

  64. freckles
    • one year ago
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    you need to go 8 more

  65. anonymous
    • one year ago
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    so 19

  66. freckles
    • one year ago
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    what ...

  67. freckles
    • one year ago
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    we had 7*10^9 this is why we are counting 9 places to the right of where the decimal was in 7 or 7.

  68. freckles
    • one year ago
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    |dw:1443932473230:dw| you have 7 more spots to move

  69. anonymous
    • one year ago
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    u said count each spot between the zero

  70. anonymous
    • one year ago
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    if the deicame was there all the way to the end is 11

  71. anonymous
    • one year ago
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    right

  72. freckles
    • one year ago
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    we only need to go 9 spots

  73. freckles
    • one year ago
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    because we had 7*10^9

  74. freckles
    • one year ago
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    for example 7*10=70 7*10^2=700 7*10^3=7000 7*10^4=70000 7*10^5=700000 and so on...

  75. freckles
    • one year ago
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    |dw:1443932712840:dw|

  76. freckles
    • one year ago
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    so we did not need those other 2 zeros at the end

  77. freckles
    • one year ago
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    I just wrote 7 and a bunch of zeros then I counted 9 spots because we had 7*10^9

  78. anonymous
    • one year ago
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    o ok that's how you write in standard form

  79. anonymous
    • one year ago
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    with only 9 zeros

  80. freckles
    • one year ago
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    yes so that number would be 7,000,000,000 if you want to put the commas there it is not necessary though

  81. anonymous
    • one year ago
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    btw if you don't mind helping me with one more but only if you want to and thx for all the help

  82. freckles
    • one year ago
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    sure

  83. anonymous
    • one year ago
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    ok thx

  84. anonymous
    • one year ago
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    The giant pandas at the zoo consume approximately 30 pounds of bamboo each day. If you were to collect data on the amount of bamboo consumed each month, which unit should you use to record your data? Explain.

  85. freckles
    • one year ago
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    what unit is it talking about?

  86. freckles
    • one year ago
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    I would assume you would use months... since you are recording the bamboo consumption each month :p

  87. anonymous
    • one year ago
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    what do you mean?

  88. freckles
    • one year ago
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    @Hero do you know what it is talking about here?

  89. freckles
    • one year ago
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    the weight unit would be pounds and the time units would be months

  90. anonymous
    • one year ago
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    what units are you talking about

  91. freckles
    • one year ago
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    but I don't know if that is what they are talking about

  92. freckles
    • one year ago
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    sounds odd to me

  93. anonymous
    • one year ago
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    i think its asking how man pound of bamboo the panda eats a month and he eats 30 pound a day

  94. anonymous
    • one year ago
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    this is what it meant about uints Units of time are second, minute, hour, day, week, month, year and decade

  95. freckles
    • one year ago
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    well we see a day he eats about 30 pounds and a month contains about 30 days so in a month he can eat about 30*30 pounds which is 900 pounds you can still use pounds for the weight unit but I guess a better choice might be kilograms

  96. anonymous
    • one year ago
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    ok so the panda eats 990 pound of bamboo each month

  97. freckles
    • one year ago
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    well if we assume he eats about 30 pounds each day and we know a month is about 30 days then in a month he can probably each about 30*30=900 pounds give or take depending on the month but the 900 part is a big number so you can use a different unit so we can work with smaller numbers

  98. Hero
    • one year ago
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    Lbs per month

  99. anonymous
    • one year ago
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    im confused am im using pounds or kilograms

  100. freckles
    • one year ago
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    I still don't get the question because you can go with either of those weight units... I don't understand why it is asking what units to use? It sounds odd to me.

  101. anonymous
    • one year ago
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    its ok if get it wrong i wont be problem just try what you think it is because right now im blanked out im so confused on what to do

  102. Hero
    • one year ago
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    At least for the first few months. And then after the numbers get two big, say after a year, then switch to more appropriate units.

  103. anonymous
    • one year ago
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    so stay with pounds

  104. anonymous
    • one year ago
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    or lbs

  105. Hero
    • one year ago
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    I would personally prefer to work with lbs as long as I could until the numbers get too large.

  106. anonymous
    • one year ago
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    ok thx for all the help and getting me to the answer

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