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anonymous

  • one year ago

I need help please.. x varies inversely as v, and x=48 when v=8. Find x when v is 64. A. x=6 B. x=64 C. x=8 D. x=48

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  1. freckles
    • one year ago
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    inversely think divides x=k/v where k is the constant of variation

  2. freckles
    • one year ago
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    use (x,v)=(48,8) to find the constant k

  3. freckles
    • one year ago
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    then once we obtain k we will go back to x=k/v where we know k now and then replace v with 64 and find x

  4. AaronAndyson
    • one year ago
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    v = k/x 8 = k/48 8*48 = k

  5. AaronAndyson
    • one year ago
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    k = 384

  6. AaronAndyson
    • one year ago
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    Now, v = k/x Taking v as 64 and k as 384 v = k/x 64 = 384/x 64x = 384 x = 384/64

  7. anonymous
    • one year ago
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    Okay. I see what you are saying.

  8. AaronAndyson
    • one year ago
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    64 times 6 is equal to 384

  9. AaronAndyson
    • one year ago
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    Therefore, x would 6.

  10. AaronAndyson
    • one year ago
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    Getting it?

  11. anonymous
    • one year ago
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    Thank you. I understood well! It made more sense. Now, would this still imply to x varies inversely as y^2, & x=4 when y=10. Find x when y=2.

  12. AaronAndyson
    • one year ago
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    x = y^2/k

  13. AaronAndyson
    • one year ago
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    2 = 10^2/k

  14. AaronAndyson
    • one year ago
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    2 = 100/k 2k = 100 k = 100/2 k = 50

  15. anonymous
    • one year ago
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    It would be 50

  16. AaronAndyson
    • one year ago
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    I think I made a mistake.

  17. anonymous
    • one year ago
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    I am understanding better. But my answer choices are a. X=16 b. X=5 c. X=80 d. X=100

  18. AaronAndyson
    • one year ago
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    What are your options?

  19. anonymous
    • one year ago
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    Those are my options.

  20. AaronAndyson
    • one year ago
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    Wait! Its x = k/y^2

  21. AaronAndyson
    • one year ago
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    x is 4 and y is 10

  22. AaronAndyson
    • one year ago
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    4 = k/10^2 4 = k/100 4*100 = k 400 = k

  23. AaronAndyson
    • one year ago
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    Now, we have to find x but y is given as 2.. Can you find x ?? k = 400 and y = 2

  24. anonymous
    • one year ago
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    So, do I divide?

  25. AaronAndyson
    • one year ago
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    x = k/y^2

  26. AaronAndyson
    • one year ago
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    k is 400 and y is 2

  27. anonymous
    • one year ago
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    So, my answer is d?

  28. AaronAndyson
    • one year ago
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    Yes absolutely right... Good Job..

  29. anonymous
    • one year ago
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    Thank you!!!!

  30. anonymous
    • one year ago
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    I think I did this one right. But I got a little confused. ~ You have 332 of fencing to enclose a rectangular region. What is the maximum area? I got a the first time and b the second time.

  31. anonymous
    • one year ago
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    A. 6889 square feet B. 6885 square feet C. 110,224 square feet D. 27,556 square feet

  32. AaronAndyson
    • one year ago
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    2L + 2W = 332 and L x W = y so from eqn 1, L = 332/2 + W so (332/2 + W) x W = y 166W + W^2 = y when derivative of y = 0 = maximum area y' = 2W + 166 0 = 2W +166 -166 = 2W W = 83 therefore as 2L +2W =332 and w = 83, L must =83 also so L x W =A 83 x 83 = 6889 A

  33. anonymous
    • one year ago
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    So, it is A and I was right the first time?

  34. AaronAndyson
    • one year ago
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    Yes...!

  35. anonymous
    • one year ago
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    Thank you! I am understanding much much better.

  36. AaronAndyson
    • one year ago
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    :)

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