anonymous
  • anonymous
I need help please.. x varies inversely as v, and x=48 when v=8. Find x when v is 64. A. x=6 B. x=64 C. x=8 D. x=48
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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freckles
  • freckles
inversely think divides x=k/v where k is the constant of variation
freckles
  • freckles
use (x,v)=(48,8) to find the constant k
freckles
  • freckles
then once we obtain k we will go back to x=k/v where we know k now and then replace v with 64 and find x

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AaronAndyson
  • AaronAndyson
v = k/x 8 = k/48 8*48 = k
AaronAndyson
  • AaronAndyson
k = 384
AaronAndyson
  • AaronAndyson
Now, v = k/x Taking v as 64 and k as 384 v = k/x 64 = 384/x 64x = 384 x = 384/64
anonymous
  • anonymous
Okay. I see what you are saying.
AaronAndyson
  • AaronAndyson
64 times 6 is equal to 384
AaronAndyson
  • AaronAndyson
Therefore, x would 6.
AaronAndyson
  • AaronAndyson
Getting it?
anonymous
  • anonymous
Thank you. I understood well! It made more sense. Now, would this still imply to x varies inversely as y^2, & x=4 when y=10. Find x when y=2.
AaronAndyson
  • AaronAndyson
x = y^2/k
AaronAndyson
  • AaronAndyson
2 = 10^2/k
AaronAndyson
  • AaronAndyson
2 = 100/k 2k = 100 k = 100/2 k = 50
anonymous
  • anonymous
It would be 50
AaronAndyson
  • AaronAndyson
I think I made a mistake.
anonymous
  • anonymous
I am understanding better. But my answer choices are a. X=16 b. X=5 c. X=80 d. X=100
AaronAndyson
  • AaronAndyson
What are your options?
anonymous
  • anonymous
Those are my options.
AaronAndyson
  • AaronAndyson
Wait! Its x = k/y^2
AaronAndyson
  • AaronAndyson
x is 4 and y is 10
AaronAndyson
  • AaronAndyson
4 = k/10^2 4 = k/100 4*100 = k 400 = k
AaronAndyson
  • AaronAndyson
Now, we have to find x but y is given as 2.. Can you find x ?? k = 400 and y = 2
anonymous
  • anonymous
So, do I divide?
AaronAndyson
  • AaronAndyson
x = k/y^2
AaronAndyson
  • AaronAndyson
k is 400 and y is 2
anonymous
  • anonymous
So, my answer is d?
AaronAndyson
  • AaronAndyson
Yes absolutely right... Good Job..
anonymous
  • anonymous
Thank you!!!!
anonymous
  • anonymous
I think I did this one right. But I got a little confused. ~ You have 332 of fencing to enclose a rectangular region. What is the maximum area? I got a the first time and b the second time.
anonymous
  • anonymous
A. 6889 square feet B. 6885 square feet C. 110,224 square feet D. 27,556 square feet
AaronAndyson
  • AaronAndyson
2L + 2W = 332 and L x W = y so from eqn 1, L = 332/2 + W so (332/2 + W) x W = y 166W + W^2 = y when derivative of y = 0 = maximum area y' = 2W + 166 0 = 2W +166 -166 = 2W W = 83 therefore as 2L +2W =332 and w = 83, L must =83 also so L x W =A 83 x 83 = 6889 A
anonymous
  • anonymous
So, it is A and I was right the first time?
AaronAndyson
  • AaronAndyson
Yes...!
anonymous
  • anonymous
Thank you! I am understanding much much better.
AaronAndyson
  • AaronAndyson
:)

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