• owlet
Determine the balanced chemical equation for this reaction. $$2C_8H_{18(g)}+25O_{2(g)}→16CO_{2(g)}+18H_2O_{(g)}$$ 0.360 mol of octane is allowed to react with 0.860 mol of oxygen. Which is the limiting reactant? My ans is oxygen because I only got 25.6 g while octane has 41.04 g. How many moles of water are produced in this reaction? I need help with this one... here is my solution: 0.63 mol O2 x (18 mol H2O /25 mol O2) = 0.576 mol of H2O but it is wrong.
Chemistry
• Stacey Warren - Expert brainly.com
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SOLVED
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