A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Help anyone????
find the asymptotes, if any, of the graph of the rational function f(x) = x/x^2 + 1
anonymous
 one year ago
Help anyone???? find the asymptotes, if any, of the graph of the rational function f(x) = x/x^2 + 1

This Question is Closed

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0if the curve is \[y = \frac{x}{x^2 + 1}\] well as for the vertical asymptotes: there are no real numbers that make the denominator zero. so the curve is continuous you can find the 1st and 2nd derivatives and as a result can find a maximum value, a minimum value and point of inflection. the only thing of not is that as x approaches infinity the curve approaches zero from above. similar for negative infinity, the curve approaches zero from below. To get a good understanding graph the curve using https://www.desmos.com/calculator if the curve is \[y = \frac{x}{x^2} + 1\] then there will be a vertical and horizontal asymptote... and to see them, just graph the curves

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if the graph is (x/x^2) + 1 ==> (x+1)/x You have a horizontal asymptote at y = 1 because your top degree, of numerator is 1 and degree of denominator is 1, too thus, if your top and bottom degrees are the same, Horizontal asymptote is the ratio of the coefficients in this case 1 over 1 for the V.asymptote, equal the denominator to zero x=0 thus V.A at x = 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks y'all. Sorry it took so long to reply, but it helped. I got it right!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.