A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

Element E reacts with oxygen to produce EO2. Identify element E if 16.5 g of it react with excess oxygen to form 26.1 g of EO2 PLEASE HELP

  • This Question is Closed
  1. Rushwr
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I got it as manganese \[E +O _{2}\rightarrow EO _{2}\] As we can see Moles of E is equal to the moles of EO2 we know moles = mass divided by molar mass If we consider the molar mass of E as M \[n _{E} = \frac{ 16.5 }{ M }\] Then write for the moles of EO2 Then the molar mass of EO2 is M+32 \[n _{EO _{2}} = \frac{ 26.1 }{ (M+32) }\] We know \[n _{E}= n _{EO _{2}}\] so \[\frac{ 26.1 }{ M+32 } = \frac{ 16.5 }{ }\] so WHEN U SIMPLIFY U GET 55 for M M is the molar mass of the element E So that is manganese

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thank you very very much.

  3. Rushwr
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    No problem :)

  4. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.