anonymous
  • anonymous
Element E reacts with oxygen to produce EO2. Identify element E if 16.5 g of it react with excess oxygen to form 26.1 g of EO2 PLEASE HELP
Chemistry
schrodinger
  • schrodinger
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Rushwr
  • Rushwr
I got it as manganese \[E +O _{2}\rightarrow EO _{2}\] As we can see Moles of E is equal to the moles of EO2 we know moles = mass divided by molar mass If we consider the molar mass of E as M \[n _{E} = \frac{ 16.5 }{ M }\] Then write for the moles of EO2 Then the molar mass of EO2 is M+32 \[n _{EO _{2}} = \frac{ 26.1 }{ (M+32) }\] We know \[n _{E}= n _{EO _{2}}\] so \[\frac{ 26.1 }{ M+32 } = \frac{ 16.5 }{ }\] so WHEN U SIMPLIFY U GET 55 for M M is the molar mass of the element E So that is manganese
anonymous
  • anonymous
thank you very very much.
Rushwr
  • Rushwr
No problem :)

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