anonymous
  • anonymous
http://prntscr.com/8nj2ma
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@hartnn
hartnn
  • hartnn
for the equation \(\Large ax^2+bx+c = 0\) to have no real roots, \(\large b^2 -4ac\) must be less than 0. so first compare x^2 +2x+c = 0 with ax^2 +bx+c = 0 and find a,b,c
anonymous
  • anonymous
a = 1, b = 2 c =1

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hartnn
  • hartnn
a= 1, b = 2 and c = c now find b^2 -4ac
anonymous
  • anonymous
2^2 - 4(1)(1) = 0
anonymous
  • anonymous
oh wait. c = c?
hartnn
  • hartnn
yes, keep c as c only
anonymous
  • anonymous
then it equals -4c+4?
hartnn
  • hartnn
\(\Large b^2-4ac < 0 \\ \large 4 - 4c < 0\) factor out the 4
hartnn
  • hartnn
or just add 4c on both sides
hartnn
  • hartnn
4 < 4c divide both sides by 4
anonymous
  • anonymous
4(1-c)?
hartnn
  • hartnn
yea, ok 4 (1-c) < 0 dividing both sides by 4 1-c < 0 or 1
hartnn
  • hartnn
which option satisfies that c>1 ??
hartnn
  • hartnn
there will be no real roots when c is greater than 1
anonymous
  • anonymous
so 0?
hartnn
  • hartnn
is 0 greater than 1 ?
anonymous
  • anonymous
3.
hartnn
  • hartnn
good! \(\huge \checkmark \)
anonymous
  • anonymous
ty
hartnn
  • hartnn
welcome ^_^

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