## anonymous one year ago URGENT!!! RLC Circuit voltage help

• This Question is Open
1. anonymous

2. IrishBoy123

from $$Q = CV$$ for the capacitor, we have $$I = C \dot V$$ so $$V(t) = \dfrac{1}{C}\int\limits_{0}^{t} I(t) \; dt$$ $$= \dfrac{1}{C}\int\limits_{0}^{t} e^{-5t} \; dt$$

3. anonymous

In your screen capture above, applying Kirchoff's Voltage Law (KVL) around the loop gives $- v(t)+v _{L}(t) + v _{c}(t) = 0$ where $v _{L}(t)$ is the voltage across the inductor. Solving gives us: $v(t) = v _{L}(t)+v _{C}(t)$ Vc(t) is given by the previous responder. $v _{L}(t) = L \frac{ di _{L} }{ dt }$ where iL is the current through the inductor, but $i_{L}(t) = i _{R}(t)+i _{C}(t)= \frac{ v _{C}(t) }{ R }+i _{C}(t)$ Since you know $v _{C}(t), i _{C}(t)$ You can now solve for $v(t)$