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anonymous

  • one year ago

Can someone please help me solve this!

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  1. anonymous
    • one year ago
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  2. Nnesha
    • one year ago
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    \[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\] that's all you need to find all 6 ratios

  3. Nnesha
    • one year ago
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    |dw:1443972456164:dw| tan B = 2/9

  4. Nnesha
    • one year ago
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    where you should put 2 and 9 ?

  5. Nnesha
    • one year ago
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    remember we are looking at angle B

  6. anonymous
    • one year ago
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    |dw:1443972579055:dw|

  7. Nnesha
    • one year ago
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    good now apply the Pythagorean theorem to find 3rd side of right triangle

  8. anonymous
    • one year ago
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    I got 9^2+2^2=c^2, 81+4=c^2, c^2=85,sqrt(85)=c

  9. Nnesha
    • one year ago
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    looks good |dw:1443972735567:dw| now use the definition iposted above to write sin cos and csc

  10. anonymous
    • one year ago
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    for cos of B I got 9(sort)/85

  11. anonymous
    • one year ago
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    sqrt*

  12. Nnesha
    • one year ago
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    looks good and we don't have to rationalize the denominator

  13. anonymous
    • one year ago
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    and for cscB i'm not sure what that would be

  14. Nnesha
    • one year ago
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    what's the reciprocal of sin ??

  15. Nnesha
    • one year ago
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    like cos and sec are reciprocal cos theta = 1/sec theta

  16. anonymous
    • one year ago
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    so csc(b)=85/2sqrt(85)?

  17. Nnesha
    • one year ago
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    what is sin B = ?

  18. anonymous
    • one year ago
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    they are asking for sinA

  19. AlexandervonHumboldt2
    • one year ago
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    @sana9 the original definitions were not those which nnesha gives you. please keep in mind that you might have a question like what is sin of 360? you will never find a 360 degrees in a triangle. so the standart school definitions will not work for such question. so keep in mind these universal things: Sinus: sin(a)=(yb)/R Cosine: cos(a)=(xb)/R Tangent: tg(a)=(yb)/(xb) picture : https://upload.wikimedia.org/wikipedia/ru/thumb/8/8f/Trig_functions.gif/250px-Trig_functions.gif sourse `wikipedia`

  20. Nnesha
    • one year ago
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    i know they are asking for sin but what is sin B = ?

  21. anonymous
    • one year ago
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    sinb=2sqrt(85)/85

  22. Nnesha
    • one year ago
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    look at this definition \[\large\rm cos \theta =\frac{ 1 }{ \sec \theta}\]\[\sin \theta = \frac{ 1 }{ \csc \theta } \]\[\tan \theta =\frac{ 1 }{ \cot \theta }\] or tan theta = sin/ cos

  23. Nnesha
    • one year ago
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    so if you find sin B you can easily find csc B

  24. anonymous
    • one year ago
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    for csc(b) I believe it's 85/2sqrt(85)

  25. Nnesha
    • one year ago
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    |dw:1443973415613:dw| don't rationalize the denominator

  26. Nnesha
    • one year ago
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    http://prntscr.com/8nn9ru

  27. Nnesha
    • one year ago
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    sin = opposite over hypotenuse so sin B =?

  28. anonymous
    • one year ago
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    ok so let me try one more time :)

  29. Nnesha
    • one year ago
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    alright take ur time!

  30. anonymous
    • one year ago
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    cos(b)=9/sqrt(85)

  31. anonymous
    • one year ago
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    csc(b)=sqrt(85)/2

  32. Nnesha
    • one year ago
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    |dw:1443973622264:dw| right

  33. Nnesha
    • one year ago
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    looks good hm

  34. anonymous
    • one year ago
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    sin(a)=9/sqrt(85)

  35. Nnesha
    • one year ago
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    right so what's sin B = ???

  36. anonymous
    • one year ago
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    sinb=2/sqrt(85)

  37. Nnesha
    • one year ago
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    right what about tan a ??

  38. anonymous
    • one year ago
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    tan=sin/cos so

  39. Nnesha
    • one year ago
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    right

  40. Nnesha
    • one year ago
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    so what is the exact value of tan A ?

  41. anonymous
    • one year ago
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    1

  42. anonymous
    • one year ago
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    so I have another question regarding find sin cos and tan

  43. anonymous
    • one year ago
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    this involves side length so I was sure how to work this out!

  44. anonymous
    • one year ago
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    wasn't*

  45. Nnesha
    • one year ago
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    no it's not 1 remember tan = sin over cos and sin = opposite over hyp cos = adjacent over hyp \[\huge\rm tan = \frac{ \frac{ o }{ h } }{ \frac{ a }{ h } }=\frac{o}{h} \times \frac{h}{a}\] multiply top fraction with the reciprocal of the bottom fraction \[\huge\rm tan =\frac{o}{\cancel{h}} \times \frac{\cancel{h}}{a}=\frac{o}{a}\] o=opposite a=adjacent so tan = opposite over adjacent

  46. anonymous
    • one year ago
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    thank you!

  47. Nnesha
    • one year ago
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    np so what is tan A ?? :+)

  48. Nnesha
    • one year ago
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    ^first question

  49. anonymous
    • one year ago
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    2/9?

  50. Nnesha
    • one year ago
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    |dw:1443974262921:dw| remember opposite and adjacent sides depends on angle 9 is adjacent side of angle B but 9 is opposite side of angle A adjacent side that touches the angle we are looking at

  51. anonymous
    • one year ago
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    9/2!

  52. Nnesha
    • one year ago
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    good ! cot =2/9 cot and tan are reciprocal of each other i think u got it just need more practice :=)

  53. anonymous
    • one year ago
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    :) thanks so much. I'm sure how to solve angles and length when knowing only 2 side lengths in a right triangle

  54. anonymous
    • one year ago
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    not sure*

  55. Nnesha
    • one year ago
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    |dw:1443974435122:dw| same question given is b and c

  56. Nnesha
    • one year ago
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    good then did you try to find 3rd side ? :=)

  57. Nnesha
    • one year ago
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    oh not sure

  58. Nnesha
    • one year ago
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    same question like last one one given are the 2 legs of `right triangle ` then always you can use Pythagorean theorem to find 3rd side

  59. anonymous
    • one year ago
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    for a I got that it equal 8

  60. anonymous
    • one year ago
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    it's just finding the angles which confuses me :/

  61. Nnesha
    • one year ago
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    8 is correct

  62. Nnesha
    • one year ago
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    ah i see |dw:1443974659273:dw| just focus one angle A for this question its easy to find angle bec u know all 3 sides you can use any ratio doesn't matter u will get the same answer!

  63. Nnesha
    • one year ago
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    |dw:1443974742902:dw|

  64. Nnesha
    • one year ago
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    let's pick sin sin A = opposite over adjacent what is opposite and adjacent side of angle A ?

  65. anonymous
    • one year ago
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    I thought sin was opposite over hyp

  66. Nnesha
    • one year ago
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    right lol sorry mistake thinking about tan

  67. anonymous
    • one year ago
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    sin(a) =8/17

  68. Nnesha
    • one year ago
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    right \[\huge\rm sin A = \frac{ 8 }{ 17}\] when we have to find anlde we use invs sin \[\large\rm A = \sin^{-1} \frac{8}{17}\]

  69. Nnesha
    • one year ago
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    angle **

  70. anonymous
    • one year ago
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    so it's 28 degrees

  71. Nnesha
    • one year ago
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    let me check :D wait plz

  72. anonymous
    • one year ago
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    ok thank you :)

  73. Nnesha
    • one year ago
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    right ! good job!

  74. anonymous
    • one year ago
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    and to find angle B we would do sin(B)=15/17 which is sin-1(15/17)=61.9 and it's exactly 62?

  75. Nnesha
    • one year ago
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    right you can round it if you want or if the direction says so

  76. Nnesha
    • one year ago
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    ohh wait directions is NO DECIMAL so round it

  77. anonymous
    • one year ago
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    the direction just mentions the exact measure

  78. Nnesha
    • one year ago
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    |dw:1443975183145:dw| so no decimal round it

  79. anonymous
    • one year ago
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    62 :D

  80. Nnesha
    • one year ago
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    good :=)

  81. anonymous
    • one year ago
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    i'm having trouble inputting the degrees sign into the answer

  82. Nnesha
    • one year ago
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    hmm

  83. Nnesha
    • one year ago
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    i guesss you don't have to put degree sign bec it says angle A so definitely the number u will put is an angle hmm i think ....

  84. anonymous
    • one year ago
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    it's wanting the degrees symbol :/

  85. Nnesha
    • one year ago
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    hmmm does it work \[\huge\rm a^o\] i'm not sure how to put on that website

  86. Nnesha
    • one year ago
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    is it a practice website or online school documeent ?

  87. anonymous
    • one year ago
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  88. anonymous
    • one year ago
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    this is what showed up

  89. Nnesha
    • one year ago
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    hmm well i think the answer we got is correct not sure what theyyy want us to do did they gave u the correct ??

  90. Nnesha
    • one year ago
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    answer >???*

  91. anonymous
    • one year ago
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    no :/

  92. anonymous
    • one year ago
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    It makes sense in terms of the math, but when I enter it in the system it's didn't recognize it

  93. Nnesha
    • one year ago
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    ye right let me think hmmm

  94. Nnesha
    • one year ago
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    how did you put degree sign ?

  95. Nnesha
    • one year ago
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    i mean degree how did you put little 0 ? :P

  96. anonymous
    • one year ago
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    I did option shift and then 8

  97. Nnesha
    • one year ago
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    maybe they just want us to write the number like 28 and 62

  98. anonymous
    • one year ago
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    I tried that but it was incorrect I think they want me to show that it's degrees

  99. Nnesha
    • one year ago
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    ye answer is right but `syntax incomplete ` :.........

  100. anonymous
    • one year ago
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    -,-

  101. Nnesha
    • one year ago
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    sorry don't know i do it b hand so

  102. anonymous
    • one year ago
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    I just emailed my instructor hopeful he responds:) thanks again so much for all your help

  103. Nnesha
    • one year ago
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    oh okay please let me know what was the mistake :=)

  104. Nnesha
    • one year ago
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    it was pleasure :=)

  105. Nnesha
    • one year ago
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    good work!

  106. anonymous
    • one year ago
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    :) I think it's just something that has to do with the keys I don't think it's the actual math

  107. Nnesha
    • one year ago
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    ye right :=)

  108. anonymous
    • one year ago
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    :D

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