find the number of numbers less than 1000 and divisible by 5 which can be formed with the digits 0 1 2 3 4 5 6 7 8 9 without repetition

- madhu.mukherjee.946

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- madhu.mukherjee.946

@imqwerty

- madhu.mukherjee.946

@imqwerty fast :P

- madhu.mukherjee.946

you are taking too long such a small sum:)

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## More answers

- imqwerty

a number divisible by 5 has either 5 at end or 0 at end
so total such number will include all numbers of 1 digit , 2 digits...
1 digit nos are easy to count they are-5
2 digits nos -
we consider 2 cases one with 0 at the end and one with 5 at the end A
A] 0 at the end
1st place can be filled with-1,2,3,4,5,6,7,8,9 and 0 is fixed at 2nd place
so total numbers=9x1=9
B]5 at end
1st place can be filled with-1,2,3,4,6,7,8,9=8nos
we didn't take 0 cause then it wuld be a single digit no we also didn't take 5 cause its already set at 2nd place
so total nos=8x1=8
total 2 digit nos=17
3 digit nos-
A] 0 at end
1st place can be filled with-1,2,3,4,5,6,7,8,9=9nos
2nd place can be filled with 8 nos cause 1 number will be consumed in this^ step=8nos left to fill 2nd place
3rd place has 0=1no
so total combinations =9x8
B] 5 at end
1st place can be filled with-1,2,3,4,6,7,8,9=8nos
2nd place can be filled with 8 nos cause we can take 0 here along with the 7 digits left after filling 1st place=8nos
3rd place has 5 =1no
total nos=8x8
total 3 digit nos=72+64=136
total nos=136+17+9
=162

- madhu.mukherjee.946

wrong answer is 154

- imqwerty

i wrote in brief :D

- imqwerty

lol wait

- imqwerty

hey i did that correct i jst made calculation mistake :P
its 72+64+17+1=154

- imqwerty

i wrote that 9 by mistake :)P
total i digit nos=1
total 2 digit nos=17
total 3 digit nos=72+64
total=154
>.<

- imqwerty

*1 digit nos

- madhu.mukherjee.946

how did you get the 3 digit numbers pls explain

- ribhu

the three digit numbers are obtained taking into account two cases

- madhu.mukherjee.946

yeah 0 and 5

- madhu.mukherjee.946

i got the 0 part just explain me the the 5 part

- ribhu

first 0: the first digit can be filled with 9 choices.. second will be 8 and since 0 is fixed so we get 9*8 = 72 numbers ending in 0 with three digits

- madhu.mukherjee.946

yeah even i got that

- ribhu

see 5 is fixed.. so first digit can be filled in 8 ways..since 0 can not come in first place so second has 8 options..every number except for 5: so we have 8*8 = 64

- ribhu

|dw:1443975974588:dw|

- madhu.mukherjee.946

yeah thank you so much i got that

- madhu.mukherjee.946

even i calculated this way and found out .mine answer matches with u

- imqwerty

(:

- madhu.mukherjee.946

thanks imqwerty : today i saw u sitting on top of the roof of your school with a monkey:P
@imqwerty

- madhu.mukherjee.946

:)))))))))))))))

- imqwerty

(: that monkey ws talkin wid me abt u

- madhu.mukherjee.946

ahhhhhhhhhhhhh

- imqwerty

yea :) he ws tellin that u 2 made a plan to go out but i came in middle e.e

- madhu.mukherjee.946

ooo very funny:P

- imqwerty

shuld i leave u 2 alone or be here e.e

- madhu.mukherjee.946

@imqwerty i'll kill you

- imqwerty

omg looool XD please kill me fast

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