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rvc
 one year ago
The coefficient of friction are µs = 0.4 and µK = 0.3 between all surfaces in contact. Determine the smallest force P required to start the 30 kg block moving if cable AB (a) is attached as shown (b) is removed
rvc
 one year ago
The coefficient of friction are µs = 0.4 and µK = 0.3 between all surfaces in contact. Determine the smallest force P required to start the 30 kg block moving if cable AB (a) is attached as shown (b) is removed

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rvc
 one year ago
Best ResponseYou've already chosen the best response.0need help with these three questions

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1sorry, my word has crashed, can you make a sketch of your exercise, please?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1part (b) the cable is removed In this case total friction force, acting on composed block is: \[{\mu _s}\left( {{m_A} + {m_B}} \right)g\] where \(\mu_s\) is the friction coefficient between the composed block and the plane, whereas \(m_A\) and \(m_B\) are the masses of the two blocks

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1dw:1443977990481:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1more precisely, what are your friction coefficients \(\mu_S\) and \(\mu_K\)?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! I know, can you indicate the surfaces to which those corfficients are referring to, please?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1when the cable is removed, then we have two blocks which form a composed block, and the friction force, at beginning of motion, is: \[\Large R = {\mu _S}\left( {{m_A} + {m_B}} \right)g\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ina shoots a large marble (Marble A, mass: 0.08 kg) at a smaller marble (Marble B, mass: 0.05 kg) that is sitting still. Marble A was initially moving at a velocity of 0.5 m/s, but after the collision it has a velocity of 0.1 m/s. What is the resulting velocity of marble B after the collision? Be sure to show your work for solving this problem along with the final answer. (5 points)

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443981768532:dw dw:1443981937384:dw
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