## rvc one year ago The coefficient of friction are µs = 0.4 and µK = 0.3 between all surfaces in contact. Determine the smallest force P required to start the 30 kg block moving if cable AB (a) is attached as shown (b) is removed

1. rvc

need help with these three questions

2. Michele_Laino

sorry, my word has crashed, can you make a sketch of your exercise, please?

3. rvc

4. rvc

5. Michele_Laino

part (b) the cable is removed In this case total friction force, acting on composed block is: ${\mu _s}\left( {{m_A} + {m_B}} \right)g$ where $$\mu_s$$ is the friction coefficient between the composed block and the plane, whereas $$m_A$$ and $$m_B$$ are the masses of the two blocks

6. Michele_Laino

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7. rvc

hmm

8. Michele_Laino

more precisely, what are your friction coefficients $$\mu_S$$ and $$\mu_K$$?

9. rvc

0.4 and 0.3 respectively

10. Michele_Laino

yes! I know, can you indicate the surfaces to which those corfficients are referring to, please?

11. Michele_Laino

when the cable is removed, then we have two blocks which form a composed block, and the friction force, at beginning of motion, is: $\Large R = {\mu _S}\left( {{m_A} + {m_B}} \right)g$

12. anonymous

Ina shoots a large marble (Marble A, mass: 0.08 kg) at a smaller marble (Marble B, mass: 0.05 kg) that is sitting still. Marble A was initially moving at a velocity of 0.5 m/s, but after the collision it has a velocity of -0.1 m/s. What is the resulting velocity of marble B after the collision? Be sure to show your work for solving this problem along with the final answer. (5 points)

13. IrishBoy123

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