## anonymous one year ago Trig! Need some help

1. anonymous

2. ribhu

3. anonymous

i'm sorry?

4. anonymous

there are not enough numbers to figure out the answer it is not complete

5. anonymous

I have an attachment :)

6. anonymous

there are not enough numbers to figure out the answer it is not complete

7. anonymous

8. anonymous

there are not enough numbers to figure out the answer it is not complete

9. Nnesha

well i know tan 45 = 1 so i guess it's 45-45-90 triangle hhmmmm

10. anonymous

I'm just curious what the sin/cos could be since tanB=1 and tan=sin/cos

11. Nnesha

well for 45-45-90 two legs would have the same length |dw:1443978946557:dw| you can use Pythagorean theorem to find 3rd one

12. hartnn

If we have the value of one trig ratio, we can find the value of any other trig ratio :)

13. anonymous

so how would we set it up? I'm a little confused

14. anonymous

|dw:1443979245240:dw|

15. hartnn

the triangle is correct! whats stopping you from finding cos B = adjacent side/ hypotenuse?

16. anonymous

I got 1/sqrt(2) for cos for sin 1/sqrt(2). As for the measure of b in radians I got pi/4

17. hartnn

faster than I thought! everything is correct :)

18. anonymous

:D thanks just making sure it's been a while since i've done trig lol

19. hartnn

know the other way to find sin and cos? or want to know?

20. Nnesha

$\huge\rm rad= \frac{ \pi }{ 180 } \times \deg$ formula to convert rad to deg

21. hartnn

$$\large \sec^2 x = 1+ \tan^2x$$ you'll get sec x $$\Large \cos x = \dfrac{1}{\sec x}$$ $$\sin^2 x+ \cos^2 x =1$$

22. Nnesha