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anonymous

  • one year ago

Suppose angle A=pi/3 radians and length of c=10

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  1. anonymous
    • one year ago
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  2. hartnn
    • one year ago
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    you have b and c, use pythagoras to find a !

  3. anonymous
    • one year ago
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    the interior angles are b=30, and a=60

  4. hartnn
    • one year ago
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    right, so you can also use the fact that, side opposite to 60 degree angle is \(\sqrt 3 /2\) times the hypotenuse

  5. anonymous
    • one year ago
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    For the length of a I tried setting up sin60=a/10

  6. hartnn
    • one year ago
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    ok, good going, so a = 10 sin 60 and sin 60 is actually \(\sqrt 3 /2\)

  7. anonymous
    • one year ago
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    so i'm a little confused what i'm supposed to do with the Sqrt(3)/2

  8. hartnn
    • one year ago
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    multiply it with 10 \(10 \dfrac{\sqrt 3}{2} = 5 \sqrt 3 \)

  9. anonymous
    • one year ago
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    oh I see, so instead of using the 60 degrees we are just multiplying sqrt(3)/2 by 10

  10. hartnn
    • one year ago
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    yeah

  11. anonymous
    • one year ago
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    makes sense! Thank you lots :D

  12. hartnn
    • one year ago
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    welcome a lots ^_^

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