## anonymous one year ago Suppose angle A=pi/3 radians and length of c=10

1. anonymous

2. hartnn

you have b and c, use pythagoras to find a !

3. anonymous

the interior angles are b=30, and a=60

4. hartnn

right, so you can also use the fact that, side opposite to 60 degree angle is $$\sqrt 3 /2$$ times the hypotenuse

5. anonymous

For the length of a I tried setting up sin60=a/10

6. hartnn

ok, good going, so a = 10 sin 60 and sin 60 is actually $$\sqrt 3 /2$$

7. anonymous

so i'm a little confused what i'm supposed to do with the Sqrt(3)/2

8. hartnn

multiply it with 10 $$10 \dfrac{\sqrt 3}{2} = 5 \sqrt 3$$

9. anonymous

oh I see, so instead of using the 60 degrees we are just multiplying sqrt(3)/2 by 10

10. hartnn

yeah

11. anonymous

makes sense! Thank you lots :D

12. hartnn

welcome a lots ^_^